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2 years ago

Question 4 of 10

Mathematics

2 answers:

shusha [124]2 years ago

8 0

Answer:

Step-by-step explanation:

add up breakfast, lunch, and dinner averages. equals 47.49 which is close to $50 for the day

alukav5142 [94]2 years ago

4 0

Answer:

Step-by-step explanation:

1. Add the costs together 10.98+13.95+22.56=47.49

2. To get an average, divide by the amount of numbers you added together. We added 3 numbers together (10.98+13.95+22.56) so we divide by 3.

47.49/3=15.83

The option closest to our number is D so we round up.

$15.83->$20

Have a good day.

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Where are the negative rational numbers placed on a vertical number line?

Y_Kistochka [10]

Answer:

B es pero que te ayude amigo

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2 years ago

ILL MARK AS BRAINLIST IF U GET IT RIGHT it’s khan

Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

given that x and y are proportional, they can be expressed as y = rx, where r is the proportionality constant. Thus, we can solve for r by doing y/x in any given point.

$\frac{8}{1.6} = \frac{15}{3} = \frac{22}{4.4} = 5$

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3 years ago

Analyze the diagram below and answer the question that follows. If 2004-02-01-02-00_files/, what is 2004-02-01-02-00_files/? A.

nadya68 [22]

Option A AY || XV given that A, Y, Z are midpoints of sides XW, VW, XV respectively. This can be obtained by knowing what similar triangles are and finding which sides are proportional.

<h3>Find the correct option:</h3>

Similar triangles: If two triangles have proportional sides the are similar.

For example, if ΔABC and ΔDEF are similar then

$\frac{AB}{DE}= \frac{BC}{EF} =\frac{AC}{DF}$

∠ABC = ∠DEF and ∠ACB = ∠DFE

Then we can write that, ΔABC ~ ΔDEF

Here in this question,

Since A, Y, Z are midpoints of sides XW, VW, XV

XA = AW

WY = VY

XZ = VZ

To consider sides AY and XV we should take triangles ΔWAY and ΔWXV

$\frac{WX}{WA} =\frac{2WA}{WA} = 2$ (since A is the midpoint of WX)

$\frac{WV}{WY} =\frac{2WY}{WY} = 2$ (since Y is the midpoint of WV)

∠AWY = ∠XWV (reflexive property)

Therefore ΔWAY and ΔWXV are similar triangles

$\frac{WX}{WA}= \frac{XV}{AY} =\frac{WV}{WY}$ = 2

∠WAY = ∠WXV and ∠AYW = ∠XVW

Hence,

AY || XV option A AY || XV given that A, Y, Z are midpoints of sides XW, VW, XV respectively.

Learn more about similar triangle here:

brainly.com/question/25882965

#SPJ1

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Analyze the diagram below and answer the question that follows. If Z, Y and A are midpoints of ΔVWX what is true about AY and XY?

A. AY || XV

B. 1/2 AY = XV

C. AY = XV

D. AY ≅ XV

5 0

2 years ago

12<br> Using side lengths only, could the triangles be similar?<br> 0.5<br> m05 1 1.5

Murljashka [212]

Answer:

$\large\boxed{\text{No.}\ \dfrac{0.5}{1}\neq\dfrac{1}{1.5}\neq\dfrac{1.5}{2}}$

Step-by-step explanation:

$\text{Let}\\ a,\ b,\ c\ -\ \text{sides of a triangle ABC, where}\ a\leq b\leq c\\d,\ e,\ f\ -\ \text{sides of a triangle}\ DE F,\ \text{where}\ d\leq e\leq f.\\\\\triangle ABC\sim\triangle DE F\iff\dfrac{a}{d}=\dfrac{b}{e}=\dfrac{c}{f}\\\\/\text{corresponding sides are in proportion}/$

$\bold{WARNING !!!}\\\\\text{No triangle like QRS exists!}\\\\1 + 0.5 = 1.5 !!!\\\\\text{The sum of the lengths of the two shorter sides of the triangle}\\\text{must be greater than the length of the longest side.}$

$\text{Despite this, let's check the ratios}$

$\text{We have:}\\\\\triangle XYZ\to a=1,\ b=1.5,\ c=2\\\triangle QRS\to d=0.5,\ e=1,\ f=1.5$

$\text{Check:}\\\\\dfrac{d}{a}=\dfrac{0.5}{1}=0.5\\\\\dfrac{e}{b}=\dfrac{1}{1.5}=\dfrac{10}{15}=\dfrac{2}{3}\\\\\dfrac{f}{c}=\dfrac{1.5}{2}=\dfrac{15}{20}=\dfrac{3}{4}\\\\\dfrac{d}{a}\neq\dfrac{e}{b}\neq\dfrac{f}{c}\neq\dfrac{d}{a}$

8 0

2 years ago

How many different 4 digit even numbers can be written using 0,5,6,3,8,7?

kherson [118]

Step-by-step explanation:

I assume the digits cannot be repeated in the numbers.

and that we don't want any numbers that start with 0, as that would be considered a 3- digit number, right ?

so, under these assumptions we have the question of in how many ways can we pull 4 digits out of 6.

if the sequence of the pulled digits would not matter, it would be combinations C(6, 4).

but because we are building actual numbers, the sequence does matter, and we use permutations P(6, 4).

P(6, 4) = 6!/(6-4)! = 6!/2! = 6×5×4×3 = 360

so, we can create 360 different numbers.

but not all of them are wanted.

we don't want the ones that start with 0. how many are those ?

since we are handling all digits in the same way and priority, there are an equal amount of numbers that start with a 0, or a 5, or a 6, or a 3, or a 8, or a 7.

so, 1/6 of the 360 numbers start with a 0, and we need to subtract them :

360 - 60 = 300 really 4-digit numbers

and from these 300 we only want even numbers. that means they can only end with 0, 6 or 8.

in the same way as for the first position, we have 1/6 of the more 300 numbers that end with one of these digits.

we allow 3 digits, so we have

3×1/6 × 300 = 1/2 × 300 = 150

that means we can write 150 different 4-digit even numbers out of these 6 digits.

6 0

2 years ago