Answer:
The answer is: y - 0 = -1/2(x - 2)
Step-by-step explanation:
Given - an equation in standard form:
-6x + 3y = 6
Solve for y:
Add 6x to both sides:
3y = 6 + 6x
y = 2 + 2x
y = 2x + 2, so the slope is 2.
The perpendicular slope is the negative inverse of 2, which is -1/2.
Point slope form is:
y - y1 = m(x - x1)
Substitute in the numbers from the point (2,0) and the slope -1/2:
y - 0 = -1/2(x - 2)
Taking it to y intercept form:
y = -1/2x + 1
Answer:
216
Step-by-step explanation:
we know that
The measurement of the external angle is the semi-difference of the arcs it comprises.
so
Step 
<u>Find the measure of the arc AJ</u>
m∠BDE=![\frac{1}{2} *[measure\ arc\ AJ-measure\ arc\ BE]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A%5Bmeasure%5C%20arc%5C%20AJ-measure%5C%20arc%5C%20BE%5D)
in this problem we have
m∠BDE=
substitute in the formula
=![\frac{1}{2} *[measure\ arc\ AJ-38\°]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A%5Bmeasure%5C%20arc%5C%20AJ-38%5C%C2%B0%5D)
=![[measure\ arc\ AJ-38\°]](https://tex.z-dn.net/?f=%5Bmeasure%5C%20arc%5C%20AJ-38%5C%C2%B0%5D)
Step 
<u>Find the measure of the arc FH</u>
m∠FGH=![\frac{1}{2} *[measure\ arc\ AJ-measure\ arc\ FH]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A%5Bmeasure%5C%20arc%5C%20AJ-measure%5C%20arc%5C%20FH%5D)
in this problem we have
m∠FGH=
substitute in the formula
=![\frac{1}{2} *[112\°-measure\ arc\ FH]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%2A%5B112%5C%C2%B0-measure%5C%20arc%5C%20FH%5D)
=![[112\°-measure\ arc\ FH]](https://tex.z-dn.net/?f=%5B112%5C%C2%B0-measure%5C%20arc%5C%20FH%5D)
therefore
<u>the answer is</u>
the measure of the arc FH is 
Answer:
1
Step-by-step explanation:
hope this helps
1 because 1 times 1 times 1 equals 1
