Step-by-step explanation:
Fractions with only factors of 2 and 5 are terminating. If not, they give repeating decimals.
Therefore 17/8 and 34/16 are terminating whereas 2/13, 5/24 and 6/7 are repeating decimals.
Answer:
Option (2)
Step-by-step explanation:
Measure of angle formed by two tangents from a point outside the circleis half the difference of the measures of the intercepted arcs.
From the figure attached,
m∠C = ![\frac{1}{2}[m(\text{major arc AB})-m(\text{minor arc AB)}]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5Bm%28%5Ctext%7Bmajor%20arc%20AB%7D%29-m%28%5Ctext%7Bminor%20arc%20AB%29%7D%5D)
= ![\frac{1}{2}[(360-m\widehat{AB})-m(\widehat{AB})]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B%28360-m%5Cwidehat%7BAB%7D%29-m%28%5Cwidehat%7BAB%7D%29%5D)
= ![\frac{1}{2}[360-2m(\widehat{AB})]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%5B360-2m%28%5Cwidehat%7BAB%7D%29%5D)
= 
= 180 - 150
= 30°
Therefore, measure of angle C will be 30°.
Option (2) is the answer.
Answer:
probability that a randomly selected page that contains only text will contain no typos that is
P(x=0) =
= 0.923
Step-by-step explanation:
<u>Poisson distribution</u>:-
Explanation of the Poisson distribution :-
The Poisson distribution can be derived as a limiting case of the binomial
distribution under the conditions that
i) p is very small
ii) n is very large
ii) λ = np (say finite
The probability of 'r' successes = 
Given the average number of typos ∝ = 0.08 per page.
probability that a randomly selected page that contains only text will contain no typos that is = 
After calculation P(x=0) =
= 0.923
probability that a randomly selected page that contains only text will contain no typos =0.923
$4680
Since 18% is 18/100 you just have to multiply the $842.4 by the reciprocal of that to find your answer
Reciprocal of 18/100 is 100/18
842.4* 100/18 equals 84240/18
84240/18 equals 4680