$a_1=9\\a_2=a_1-10=9-10=-1\\a_3=a_2-10=-1-10=-11\\a_4=a_3-10=-11-10=-21\\\vdots\\\\a_n=\left\{\begin{array}{ccc}a_1=9\\a_n=a_{n-1}-10\end{array}\right$

4 0

4 years ago

Which of the following rational functions is graphed below

Mrac [35]

C.
the dotted line is the vertical asymptote, the value that x can never be. x can not be 4 this case, because x+4, the denominator, cannot be 0.

6 0

3 years ago

Read 2 more answers

What is the area of this ^2

Ad libitum [116K]

<h2>Question:- Area of the given diagram</h2>

<h2>Answer :- </h2>

Divide the diagram as shown in attachment.

Now first calculate the area of the rectangle having side 1 and 12

So area = length ×breadth

Area = 1× 12 = 12 unit²

Now find the Area of the remaining triangle with sides 12,13,5 units

$Area = \frac{1}{2} \times base \times height \:$

Now put the value as -> base= 5 and height= 12

$Area = \frac{1}{2} \times base \times height \: \\ Area = \frac{1}{2} \times 5 \times 12 \\ Area = \frac{1}{ \cancel2} \times 5 \times \cancel{12}^{ \: \: 6} \\ Area = 5 \times 6 \\ Area = 30 \: units^{2}$

Now add both areas for your answer

$Area{ \tiny{1}} = 12 {units}^{2} \\ Area{ \tiny2} = 30 {units}^{2} \\ Area{ \tiny{total}} = Area{ \tiny{1}} + Area{ \tiny{2}} \\ Area{ \tiny{total}} = 12 + 30 = 42 {units}^{2}$

8 0

3 years ago