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3 years ago

Write a word phrase for the following algebraic expression: 8n-3.

Mathematics

2 answers:

Harlamova29_29 [7]3 years ago

7 0

Here is the expression:

$8n-3$

"n" is defined as a variable. In the expression, "n" is being multiplied by 8.

$Current\ Expression: 8\ \times\ a\ number\ n$

"-" is the subtraction sign. You are going to be subtracting. Most of the time, when subtracting, "decreased by" is often used for subtracting.

$Current\ Expression: 8\ \times\ a\ number\ n\ decreased\ by$

3 is just 3. You can just add 3 to the expression.

$Current\ Expression: 8\ \times\ a\ number\ n\ decreased\ by\ 3$

ANSWER: 8 times a number n decreased by 3

exis [7]3 years ago

3 0

eight times n minus three.

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Maths<br> Share £72 in the ratio 2:7

avanturin [10]

2+7= 9
72 / 9 = 8
8 * 2 = 16
<span>8 * 7 = 56
</span>16:56
<span>
Key:
</span>* = times
<span>/ = divide</span>

5 0

3 years ago

How do I set this up

Mrac [35]

To justify the yearly membership, you want to pay at least the same amount as a no-membership purchase, otherwise you would be losing money by purchasing a yearly membership. So set the no-membership cost equal to the yearly membership cost and solve.

no-membership costs $2 per day for swimming and $5 per day for aerobic, in other words, $7 per day. So if we let d = number of days, our cost can be calculated by "7d"

a yearly membership costs $200 plus $3 per day, or in other words, "200 + 3d"

Set them equal to each other and solve:

7d = 200 + 3d

4d = 200

d = 50

So you would need to attend the classes for at least 50 days to justify a yearly membership. I hope that helps!

5 0

2 years ago

What is 1/5 miles in units to 1/65 hours

Anastaziya [24]

Answer:

13m/h

Step-by-step explanation:

1/5m=1/65h

65/5m=h

13m=h

13 miles per hour.

7 0

3 years ago

Read 2 more answers

the average age of four men is 40. If the sum of the ages of three of them is 115, what's the age of the fourth man?

pashok25 [27]

Answer:

Step-by-step explanation:

if 1 man is 37

and 1 man is 43

the 3rd man is 45

they add to 115

to average 40, we gotta add 35

this old mans giving u that!

3 0

1 year ago

Evaluate the following limit:

Makovka662 [10]

If we evaluate the function at infinity, we can immediately see that:

$\large\displaystyle\text{$\begin{gathered}\sf \bf{\displaystyle L = \lim_{x \to \infty}{\frac{(x^2 + 1)^2 - 3x^2 + 3}{x^3 - 5}} = \frac{\infty}{\infty}} \end{gathered}$}$

Therefore, we must perform an algebraic manipulation in order to get rid of the indeterminacy.

We can solve this limit in two ways.

By comparison of infinities:

We first expand the binomial squared, so we get

$\large\displaystyle\text{$\begin{gathered}\sf \displaystyle L = \lim_{x \to \infty}{\frac{x^4 - x^2 + 4}{x^3 - 5}} = \infty \end{gathered}$}$

Note that in the numerator we get x⁴ while in the denominator we get x³ as the highest degree terms. Therefore, the degree of the numerator is greater and the limit will be \infty. Recall that when the degree of the numerator is greater, then the limit is \infty if the terms of greater degree have the same sign.

Dividing numerator and denominator by the term of highest degree:

$\large\displaystyle\text{$\begin{gathered}\sf L = \lim_{x \to \infty}\frac{x^{4}-x^{2} +4 }{x^{3}-5 } \end{gathered}$}\\$

$\ \ = \lim_{x \to \infty\frac{\frac{x^{4} }{x^{4} }-\frac{x^{2} }{x^{4}}+\frac{4}{x^{4} } }{\frac{x^{3} }{x^{4}}-\frac{5}{x^{4}} } }$

$\large\displaystyle\text{$\begin{gathered}\sf \bf{=\lim_{x \to \infty}\frac{1-\frac{1}{x^{2} } +\frac{4}{x^{4} } }{\frac{1}{x}-\frac{5}{x^{4} } } \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ =\frac{1}{0}=\infty } \end{gathered}$}$

Note that, in general, 1/0 is an indeterminate form. However, we are computing a limit when x →∞, and both the numerator and denominator are positive as x grows, so we can conclude that the limit will be ∞.

5 0

1 year ago