C = 3
You isolate the variable by dividing each side by factors that don’t contain the variable
For this case the main function is:
f (x) = x ^ 2
We are going to apply the following transformations:
Vertical translations
Suppose that k> 0:
To graph y = f (x) + k, move the graph of k units up.
We have then:
f (x) = x ^ 2 + 5
Horizontal translations
Suppose that h> 0
To graph y = f (x + h), move the graph of h units to the left.
We have then:
f (x) = (x + 1) ^ 2 + 5
Answer:
f (x) = (x + 1) ^ 2 + 5
Given equation :−1/2 (x+2) + 112x = 3
We have -1/2 in front of parenthesis on left side .
It's better to remove fraction in an equation, in order make it easier to solve.
In order to remove 2 from denominator of 2, we need to multiply each and every term by 2.
Multiplying each term in the equation by 2, we get
2* −1/2(x+2) +2* 112x = 2*3.
On simplifying this step, we get
-1(x+2) +224x = 6.
Distributing -1 over (x+2), we get
-x -2 +224x = 6
Combining like terms on left side, -x+224x=223x
223x -2 = 6
Adding 2 on both sides, we get
223x -2+2 = 6+2
223x = 8
Dividing both sides by 223, we get
223x/223 = 8/223.
x= 8/223.
Answer: 48
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Define the number of cakes they baked in term of x
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Let the number of cakes Kay baked be x
Kay = x
Tim = 3x ← Tim baked 3 times as many as Kay
Griff = 1.5x ← Griff baked 1/2 as many as Tim
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Construct the equation and solve for x
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The total number of cakes baked was 88.
x + 3x + 1.5x = 88 ← Combine like terms
5.5 x = 88 ← Divide by 5.5
÷5.5 ÷5.5
x = 16
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Find the number of cakes each baked
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Kay = x = 16
TIm = 3x = 16 x 3 = 48
Griff = 1.5x = 1.5(16) = 24
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Answer: Tim baked 48 cakes.
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