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hammer [34]
3 years ago
14

Can anyone help with this?

Mathematics
1 answer:
ss7ja [257]3 years ago
7 0

The vertex is (3,5).

There is no x intercept. Because

0=(x-3)^2+5 has no real solutions.

The y intercept is 14. Because:

y=(0-3)^2+5=14



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\dfrac{\partial\vec r}{\partial v}\times\dfrac{\partial\vec r}{\partial u}=-u\,\vec k

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