Two planes left the airport traveling in the same direction. The distance Plane A traveled is modeled by the function d(t)=290t
1 answer:
Answer:
The distance Plane A traveled in 1 h is greater than the distance Plane B traveled in 1 h.
Step-by-step explanation:
The equation of the distance traveled by Plane A is
The plane B traveled 540 miles in 2 hours.
So in 1 hour, plane B traveled 540/2 = 270 miles:
How does the distance Plane A traveled in 1 hour compare to the distance Plane B traveled in 1 hour?
Plane A:
d(1) = 290*1 = 290
Plane A traveled 290 miles in 1 hour.
Plane B travaled 270 miles in 1 hour.
So the correct answer is:
The distance Plane A traveled in 1 h is greater than the distance Plane B traveled in 1 h.
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Step-by-step explanation:
First, let's move the to the right-hand side so we can determine what constant we'll need on the left-hand side to complete the square:
From here, since the coefficient of the term is
, we know the square will be
(since
it's half of
).
To complete this square, we will need to add to both sides of the equation:
Now we can take the square root of both sides to figure out the solutions to :