a2+b2=c2
a=x
b=24
c=26
a2+24 squared=26 squared
a2+576=676
-576 -576
a2=100
Then, square root both sides.
It should be a/x=10
Answer:
7
Step-by-step explanation:
twice for joey's age so joeys age is 2 double that it will be 4 so 3+4=7
width = x
length = 2x+8
area = l x w
x<span>(2x+8)</span>=120
<span><span>2<span>x^2</span>+8x−120=0 </span>
</span>
<span><span><span>x^2</span>+4−60=0 </span></span>
<span><span><span>(x+10)</span><span>(x−6)</span>=0</span>
</span>
<span><span>x=−10 and x=6 </span></span>
<span><span> width has to be a positive number</span></span>
Width = <span>6
</span> inches.
So, we know that a^2 + b^2 = c^2. Right? That is called the Pythagorean Theorem.
In this case. We can say that 39 is a, 40 is b, and x is c.
NOTE: It doesn't really matter whether 39 is a or b. a & b are just the two legs of the right triangle.
So, if we say that 39 is a, 40 is b, and x is c. We can plug it into the Pythagorean Theorem.
39^2 + 40^2 = x^2
I'll let you take it from there.
Answer:
that is the solution to the question
