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tekilochka [14]
2 years ago
15

A jar is full of 100 coins. All of the coins are either nickels or dimes.

Mathematics
1 answer:
Elza [17]2 years ago
5 0

Answer:

73 nickels, 27 dimes

Step-by-step explanation:

x+y=100

5x+10y=635

x=100-y

5(100-y)+10y=635

500-5y+10y=635

500+5y=635

5y=135

y=27

5x+10(27)=635

5x+270=635

5x=365

73

73+27=100

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Given:

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To find:

The sum of all the terms in the progression.

Solution:

We have,

First term : a=-2

Common difference : d = 5 - (-2)

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nth term of an A.P. is

a_n=a+(n-1)d

where, a is first term and d is common difference.

a_n=-2+(n-1)(7)

According to the equation, a_n>200.

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Divide both sides by 7.

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Add 1 on both sides.

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Sum of n terms of an A.P. is

S_n=\dfrac{n}{2}[2a+(n-1)d]

Substituting n=30, a=-2 and d=7, we get

S_{30}=\dfrac{30}{2}[2(-2)+(30-1)7]

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S_{30}=15(199)

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Therefore, the sum of all the terms in the progression is 2985.

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