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sweet [91]
2 years ago
14

HELP PLSSSSS

Mathematics
1 answer:
ludmilkaskok [199]2 years ago
4 0

Answer:

a=21

AB=23.9

BC=19.5

CD=(23.9)

AD=19.5

Step-by-step explanation:

Each pair of parallel sides are equal in a parallelogram. Sense both pairs use the same variable we can just choose the easiest to solve which would be:

a-1.5=19.5

add 1.5 to both sides

a=21

now substitute 21 in for a in each equation.

AB=CD so

AB=23.9

BC=AD so

BC=19.5

CD=(21)+2.9 so

CD=(23.9)

AD is given so

AD=19.5

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Answer:

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Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the giveninterval.

Poisson distribution with mean of 3.2 bits/kb (per kilobyte).

This means that \mu = 3.2kb, in which kb is the number of kilobytes.

(a) What is the probability of 5 bits being in error during the transmission of 1 kb?

This is P(X = 5) when \mu = 3.2

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 5) = \frac{e^{-3.2}*3.2^{5}}{(5)!} = 0.1140

11.40% probability of 5 bits being in error during the transmission of 1 kb

(b) What is the probability of 8 bits being in error during the transmission of 2 kb?

This is P(X = 8) when \mu = 2*3.2 = 6.4

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 8) = \frac{e^{-6.4}*6.4^{8}}{(8)!} = 0.1160

11.60% probability of 8 bits being in error during the transmission of 2 kb

(c) What is the probability of no error bits in 3kb?

This is P(X = 0) when \mu = 3*3.2 = 9.6

Then

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-9.6}*9.6^{0}}{(0)!} = 0.0001

0.01% probability of no error bits in 3kb

7 0
3 years ago
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Softa [21]
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3 years ago
An acre measures 4840 square yards. In a city, a lot on which a single-
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The lot is <u>9.2% of the an acre.</u>

<u>Given:</u>

Area of an acre = 4840 sq. yards

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Convert the area of the lot to feet (9 ft^{2} = yd^{2}):

<em>Therefore:</em>

Area of lot = \frac{4,000}{9} = 444.4 $ yd^{2}

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brainly.com/question/20730855

7 0
3 years ago
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Step-by-step explanation:

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Answer:

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The total number of ways the jury can be picked is the combination of a pool of 35 people and choosing 12 is; C(30,12) = 30!/((12!)(30 - 12)!)

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