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3 years ago

11

PLEASE HELP!!!!!!!!!!

1 answer:

IRISSAK [1]3 years ago

3 0

Answer:

A

Step-by-step explanation:

hope this helps!

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If bookstore ABC Books determines it is going to sell books at its profit-maximizing price of $19 in a market facing monopolisti

Nesterboy [21]

Answer:

$8.

Step-by-step explanation:

See attached picture.

6 0

3 years ago

At most Nate can run 0.1 of a mile in a minute. If he is given 13.9 minutes to run as far as he can, how many miles dan Nate run

nadezda [96]

(.1mi/1min)
1.39mi/13.9 min
You have to multiply the bottom and the top by the same number to get the answer, you're trying to make the denominator 13.9 for the amount do minutes so you multiply the numerator by 13.9 to get the numerator

3 0

3 years ago

I WILL THANK YOU THE QUESTION IS THE PHOTO! Pls answer ASAP IM GIVING 40 POINTS!!!

yarga [219]

Answer:

C or D

Step-by-step explanation:

7 0

3 years ago

Steve likes to entertain friends at parties with "wire tricks." Suppose he takes a piece of wire 60 inches long and cuts it into

Alex_Xolod [135]

Answer:

a) the length of the wire for the circle = $(\frac{60\pi }{\pi+4}) in$

b)the length of the wire for the square = $(\frac{240}{\pi+4}) in$

c) the smallest possible area = 126.02 in² into two decimal places

Step-by-step explanation:

If one piece of wire for the square is y; and another piece of wire for circle is (60-y).

Then; we can say; let the side of the square be b

so 4(b)=y

b= $\frac{y}{4}$

Area of the square which is L² can now be said to be;

$A_S=(\frac{y}{4})^2 = \frac{y^2}{16}$

On the otherhand; let the radius (r) of the circle be;

2πr = 60-y

$r = \frac{60-y}{2\pi }$

Area of the circle which is πr² can now be;

$A_C= \pi (\frac{60-y}{2\pi } )^2$

$=( \frac{60-y}{4\pi } )^2$

Total Area (A);

A = $A_S+A_C$

= $\frac{y^2}{16} +(\frac{60-y}{4\pi } )^2$

For the smallest possible area; $\frac{dA}{dy}=0$

∴ $\frac{2y}{16}+\frac{2(60-y)(-1)}{4\pi}=0$

If we divide through with (2) and each entity move to the opposite side; we have:

$\frac{y}{18}=\frac{(60-y)}{2\pi}$

By cross multiplying; we have:

2πy = 480 - 8y

collect like terms

(2π + 8) y = 480

which can be reduced to (π + 4)y = 240 by dividing through with 2

$y= \frac{240}{\pi+4}$

∴ since $y= \frac{240}{\pi+4}$ , we can determine for the length of the circle ;

60-y can now be;

= $60-\frac{240}{\pi+4}$

= $\frac{(\pi+4)*60-240}{\pi+40}$

= $\frac{60\pi+240-240}{\pi+4}$

= $(\frac{60\pi}{\pi+4})in$

also, the length of wire for the square (y) ; $y= (\frac{240}{\pi+4})in$

The smallest possible area (A) = $\frac{1}{16} (\frac{240}{\pi+4})^2+(\frac{60\pi}{\pi+y})^2(\frac{1}{4\pi})$

= 126.0223095 in²

≅ 126.02 in² ( to two decimal places)

4 0

4 years ago

Solve 2x^2 − 8x = −7

kenny6666 [7]

Answer:

The answer to your question is below

Step-by-step explanation:

2x² - 8x = - 7

Divide by 2

$\frac{2}{2} x^{2} - \frac{8}{2} x = \frac{-7}{2}$

Complete the trinomial

$x^{2} - 4x + (2)^{2} = \frac{-7}{2} + (2)^{2}$

Simplify

$x^{2} - 4x + (2)^{2} = \frac{- 7 + 4}{2}$

$x^{2} - 4x + 4 = \frac{-3}{2}$

Factor

(x - 2)² = $\frac{-3}{2}$

Get the square root

$\sqrt{(x - 2)^{2}} = \sqrt{\frac{-3}{2}}$

Simplification

x - 2 =± $\sqrt{\frac{3}{2}} i$

x₁ = 2 + $\sqrt{\frac{3}{2}} i$

x₂ = 2 - $\sqrt{\frac{3}{2}}$

6 0

3 years ago