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2 years ago

What transformation maps quadrilateral EFGH to quadrilateral QRSP?

Mathematics

2 answers:

irga5000 [103]2 years ago

7 0

Hello there

the answer to number 4 is.

90° degrees counterclockwise rotation

hope this helps

thank you

Best Regards Queen Z

sashaice [31]2 years ago

6 0

The markings indicate the figures are congruent. The orientation of both figures is clockwise, so no reflection is involved. The direction of QR appears to be 90° counterclockwise from the direction of EF, It appears as though the center of rotation is somewhere in the triangle EGS.

The transformation appears to be a 90° CCW rotation.

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Nathaly lost 29 cups of sugar by accidentally spilling it all over the floor after she cleaned it up,she asked her neighbor she

Taya2010 [7]

She needs 3 3/4 cups more

Step-by-step explanation:

(I think you accidently put the 18 3/4 part twice) but anyways if you add 3/4 and 1/2 you get 1 and 1/4 that will be important later then you do 18 + 6 = 24 and then add your 1 and 1/4 to get a total of 25 1/4 then you just minus that from 29 and get 3 and 3/4

Hope this Helps!

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2 years ago

1. Maya is selling bracelets and necklaces she made to make money for summer vacation. The bracelets cost $4 and the necklaces c

miv72 [106K]

Answer:

1. B

2.D

Step-by-step explanation:

x = $80 profit made if sold all carrots.

y = $120 if all tomatoes are sold.

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2 years ago

Eduardo spent $34 on a magazine and some candy bars if the magazine cost $6 and each candy bar cost $4 then how many candy bars

tatiyna

Answer: 7 candy bars

Step-by-step explanation:

First we need to subtract the cost of the magazine from the total cost

$34-$6=$28

Now the $28 that remains is the cost of all the candy bars, so if we divide by the price, we will get the amount.

$28/$4=7 candy bars

7 0

3 years ago

Which statement is correct?

MakcuM [25]

Answer:

the third 1

Step-by-step explanation:

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2 years ago

Use the given degree of confidence and sample data to construct a confidence interval for the population mean mu.Assume that the

worty [1.4K]

Answer:

95% confidence interval for the true mean cholesterol content of all such eggs.

(173.8175 , 196.1825)

Step-by-step explanation:

Step(i):-

Given mean of the sample x⁻ = 185 milligrams

Given standard deviation of the sample 'S' = 17.6 milligrams

Level of significance

∝ = 0.05

$t_({\frac{\alpha }{2} , n-1 }) = t_{0.025 ,11} = 2.2010$

Step(ii):-

95% confidence interval for the true mean cholesterol content of all such eggs.

$(x^{-} - t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} } , x^{-} + t_{\frac{\alpha }{2} } \frac{S}{\sqrt{n} })$

$(185 - 2.2010 \frac{17.6}{\sqrt{12} } , 185 + 2.2010 \frac{17.6}{\sqrt{12} })$

( 185 - 11.1825 , 185 + 11.1825)

(173.8175 , 196.1825)

Final answer:-

95% confidence interval for the true mean cholesterol content of all such eggs.

(173.8175 , 196.1825)

3 0

2 years ago