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Anastasy [175]
3 years ago
11

What transformation maps quadrilateral EFGH to quadrilateral QRSP?

Mathematics
2 answers:
irga5000 [103]3 years ago
7 0

Hello there

the answer to number 4 is.

90° degrees counterclockwise rotation

hope this helps

thank you

Best Regards Queen Z

sashaice [31]3 years ago
6 0

The markings indicate the figures are congruent. The orientation of both figures is clockwise, so no reflection is involved. The direction of QR appears to be 90° counterclockwise from the direction of EF, It appears as though the center of rotation is somewhere in the triangle EGS.

The transformation appears to be a 90° CCW rotation.

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Find the area of a square with sides of length 12
Maru [420]

Answer:

144

Step-by-step explanation:

12x12=144

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4 years ago
timy earns $7.75 from his part-time job at walmart. He worked 5 hours on monday, 3 hours on wednesday and 7 hours on friday. How
Alex Ar [27]

Answer:

Timy earned $116.25 this week.

Step-by-step explanation:

Timy earns $7.75 from his part-time job at Walmart.

Let us suppose this is his hourly rate.

He worked 5 hours on Monday, 3 hours on Wednesday and 7 hours on Friday.

So, total hours he worked = 5+3+7=15 hours

Now, his earnings will be = 15\times7.75=116.25 dollars

Therefore, Timy earned $116.25 this week.

4 0
3 years ago
Read 2 more answers
Madison is starting her own sewing business. Madison thinks she will do a better job than her competitors, so she thinks she can
ira [324]

Answer:

$681.50

Step-by-step explanation:

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8 0
3 years ago
6 yd<br> 11 yd<br> 16 yd<br> 5 yd<br> 13 yd
Juli2301 [7.4K]

Answer: We find out what these numbers have in common for example:

11yd+5yd=16yd so what is 13yd+6yd it is 19yd. This is your answer.

Step-by-step explanation: I hope this helps!

5 0
3 years ago
Please help I will give out brainliest
kolbaska11 [484]

Hey There!! ~

The answer to this is: the upper bound for the length is 21.5cm. Lower and Upper Bounds

The lower bound is the smallest value that will round up to the approximate value.

The upper bound is the smallest value that will round up to the next approximate value.

Ex:- a mass of 70 kg, rounded to the nearest 10 kg, The upper bound is 75 kg, because 75 kg is the smallest mass that would round up to 80kg.

Here , A length is measured as 21cm correct to 2 significant figures. We need to find what is the upper bound for the length . let's find out:

As discussed above , upper bound for any number will be the smallest value in decimals which will round up to next integer value . So , for 21 :

⇒  21.5cm.

21.5 cm on rounding off will give 22 cm . So , the upper bound for the length is 21.5cm.

Hope It Helped!~

ItsNobody~

7 0
3 years ago
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