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Aneli [31]
2 years ago
11

In sentence 3 (reproduced below), the writer wants to ensure that the connotation of the underlined word is appropriate to the c

ontext of the sentence. Adolescents have unique sleep patterns, and with an early school start, many are doggedly tired, leading to serious health and safety risks. Which of the following versions of the underlined word would best accomplish this goal?.
SAT
1 answer:
charle [14.2K]2 years ago
6 0

The best option that would accomplish the goal for using "doggedly" is C. <u>chronically</u>.

<h3>What is point of the underlined word?</h3>
  • Doggedly refers to something that is showing persistence.
  • It means therefore, that adolescents are persistently tired.

The best word to replicate this meaning would be "chronically" because it is a negative word that is used to described a condition that is persistent much like the persistent fatigue of these adolescents.

In conclusion, option C is correct.

Find out more examples of "chronic" in use at brainly.com/question/934133.

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The box plot and table represent data on the number of points scored per game for two players, player a and player b, in their l
klemol [59]

If you were the coach, the player I would want on my team would be player A.

<h3>Which player would I want on my team?</h3>

The player I would want on my team is the better player.

Statistics of Player A:

Minimum score = 14

Maxium score = 40

First quartile = 25

Median = 31

Third quartile = 33

Statistics for Player B:

Arranging Player B's scores in ascending order: 8, 21, 22, 22, 25, 25, 26, 28, 29, 31, 32, 35, 46

Minimum score = 8

Maxium score = 46

First quartile = 1/4(13 + 1) = 22

Median = 26

Third quartile = 3/4(13 + 1) = 31.5

Please find attached the complete question. To learn more about median, please check: brainly.com/question/20434777

5 0
2 years ago
Shakespeare’s tragic heroes are complex, round characters. Greek tragedies had “good” characters who made mistakes, but Shakespe
gulaghasi [49]
I have not read any shakespeare books yet but I can say that we are all flawed. some in more ways than others, but we are all different and have flaws just like everyone else. So the answer i’d go for is B. flawed.
6 0
2 years ago
Describe the Color Yellow?
8_murik_8 [283]

Answer:

Explanation:

Yellow is energizing without being noisy or irate." "It is a warm, delicate tone, similar to an infant chick, or the glow of daylight in springtime gushing through a window heating up a fix on the rug."

3 0
3 years ago
The graph shows the price of green tea compared to the amount supplied by producers. What does this graph suggest about green te
Usimov [2.4K]

The information which can be deduced from this graph on green tea are:

B. Green tea is inelastic in terms of supply.

E. The supply of green tea does not change sharply with the price.

<h3>What is supply?</h3>

Supply can be defined as the total quantity of goods or services that are demanded by consumers at a given period of time.

<h3>The types of supply.</h3>

In Economics, there are two main types of supply and these include:

  • Elastic supply
  • Inelastic supply

<h3>What is inelastic supply?</h3>

Inelastic supply is a situation that occurs when the quantity of goods or services that the producers are willing to produce, doesn't change as the price of goods or services increases.

Read more on supply here: brainly.com/question/11898489

3 0
2 years ago
Friction: a 50-kg box is resting on a horizontal floor. A force of 250 n directed at an angle of 30. 0° below the horizontal is
sergejj [24]

The net forces on the box parallel and perpendicular to the surface, respectively, are

∑ F[para] = (250 N) cos(-30.0°) - F[friction] = (50 kg) a

and

∑ F[perp] = F[normal] + (250 N) sin(-30.0°) - F[weight] = 0

where a is the acceleration of the box. (We ultimately don't care what this acceleration is, though.)

To decide whether the friction here is static or kinetic, consider that when the box is at rest, the net force perpendicular to the floor is

∑ F[perp] = F[normal] - F[weight] = 0

so that, while at rest,

F[normal] = (50 kg) g = 490 N

Then with µ[s] = 0.40, the maximum magnitude of static friction would be

F[s. friction] = 0.40 (490 N) = 196 N

so that the box will begin to slide if it's pushed by a force larger than this.

The horizontal component of our pushing force is

(250 N) cos(-30.0°) ≈ 217 N

so the box will move in our case, and we will have kinetic friction with µ[k] = 0.30.

Solve the ∑ F[perp] = 0 equation for F[normal] :

F[normal] + (250 N) sin(-30.0°) - F[weight] = 0

F[normal] - 125 N - 490 N = 0

F[normal] = 615 N

Then the kinetic friction felt by the box has magnitude

F[k. friction] = 0.30 (615 N) = 184.5 N ≈ 185 N

8 0
2 years ago
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