Answer:
16.03m(2dp)
Explanation:
Ep=m x g x h
1100=7.0x 9.8( gravitational field strength) x h
Height= 1100/7.0 x 9.8
=16.03498542
= 16.03m (2dp)
niAnswer:
(A) Vx = -9.14ωCosωt,
Vy = 9.14ωSinωt
(B) ax =9.14ω²Sinωt,
ay = 9.14ω²Cosωt
Explanation:
The velocity of a body ia the time derivative of the poaition function of the body with respect to time. Given equations x = −9.14 sin ωt and y = 4.00 − 9.14 cos ωt,
All we need to do to get the velocity is to differentiate each of the equation above with respect to time in order to get Vx and Vy required of us.
Vx = dx/dt = -9.14ωCosωt and
Vy = dy/dt = 9.14ωSinωt
In order to get the acceleration we differentiate the velocity function with respect to time. That is,
A = dv/dt
ax = dVx/dt = 9.14ω²Sinωt
ay = dVx/dt = 9.14ω²Cosωt
Answer:
MOMENTUM of the football player before collision is 110×8 =880
Explanation:
Answer:
a) The magnitude of the thrust provided by the jet's engines is 4840 newtons.
b) The magnitude of the tension in the cable connecting the jet and glider is 572 newtons.
Explanation:
a) By Newton's laws we construct the following equations of equilibrium. Please notice that both the glider and the jet experiments has the same acceleration:
Jet
(1)
Glider
(2)
Where:
- Thrust of jet engines, measured in newtons.
- Tension in the cable connecting the jet and glider, measured in newtons.
, - Masses of the glider and the jet, measured in kilograms.
- Acceleration of the glider-jet system, measured in meters per square second.
If we know that , and , then the solution of this system of equations:
By (2):
By (1):
The magnitude of the thrust provided by the jet's engines is 4840 newtons.
b) The magnitude of the tension in the cable connecting the jet and glider is 572 newtons.
Answer:
Single replacement
Explanation:
A reaction in which one element replaces a similar element is called single replacement. In this case, C is replacing A.