Translation
A tractor pulling a cart loaded with sugar cane travels down the straight path of a farm at a speed of 20 km / h. If at 3:00 p.m.you pass the Finca Las Margaritas, what time will you arrive at the Las Ilusiones farm, located on the same road, if the distance between the two farms is 60 km
Answer:
6.00 pm
Explanation:
Speed is given by dividing distance by time and expressed as s=d/t. Making time the subject of the formula then t=d/s where s is the speed, d is distance covered and t is the time taken. Substituting 20 km/h for s and 60 km for d then t=60/20=3 hours
Adding 3 hours to 3 pm we get 6pm
Therefore, the time to reach the destination if the speed is constantly maintained is 6.00 pm
Answer: The time required for the impluse passing through each other is approximately 0.18seconds
Explanation:
Given:
Length,L = 50m
M/L = 0.020kg/m
FA = 5.7×10^2N
FB = 2.5×10^2N
The sum of distance travelled by each pulse must be 50m since each pulse started from opposite ends.
Ca(t) + CB(t) = 50
Where CA and CB are the velocities of the wire A and B
t = 50/ (CA + CB)
But C = Sqrt(FL/M)
Substituting gives:
t = 50/ (Sqrt( FAL/M) + Sqrt(FBL/M))
t = 50/(Sqrt 5.7×10^2/0.02) + (Sqrt(2.5×10^2/0.02))
t = 50 / (168.62 + 111.83)
t = 50/280.15
t = 0.18 seconds
Answer:
(a): It spends on the trip 2.75 hr (2 hours 45 minutes)
(b): The person travels 213.9 km.
Explanation:
Vp= 77.8 km/h
V1= 89.5 km/h
V2= 0 km/h
t2= 0.36hr
t1= ?
Vp= (V1*t1 + V2*t2) / (t1 + t2)
clearing t1:
t1= 2.39 hr
Trip time= t1+t2
Trip time= 2.75 hr (a)
Distance traveled= V1*t1
Distace traveled= 213.9 km (b)
Answer:
Horse/Speed
55 mph
rounded to the tenth? either 60 or 50
but 350 would stay like that i believe!
Explanation:
