Answer:
Um it might be 1 but feel free to correct me if I'm wrong
Answer:77
Just multiply the numbers
7/13 * 143
= (7*143)/13
= 1001/13
= 77
So the answer is 77
Answer:
h=24
Step-by-step explanation: In order to solve this we have to apply the Pythagorean Therom which states a^2+b^2=c^2. c^2 being the the hypotenuse. First we have to plug in the values so the new equation is a^2+7^2=25^2. Now we simplify to get a^2+49=625. We can now subtract 49 from both sides to get a^2=576. The final step is to square it to get a=24. So h=24
Answer:
6.20%
Step-by-step explanation:
Missing question and graph attached.
Given: Total number of sample collected for female between age 20-29 is 548.
34 females that weighed over 250 pounds.
Now, finding percentage of females aged 20 to 29 weighed over 250 pounds.
Percent of Female over 250 pound aged 20-29= ![\frac{Number\ of \ females\ over\ 250\ pounds}{Total\ number\ of\ females\ aged 20-29} \times 100](https://tex.z-dn.net/?f=%5Cfrac%7BNumber%5C%20of%20%5C%20females%5C%20over%5C%20250%5C%20pounds%7D%7BTotal%5C%20number%5C%20of%5C%20females%5C%20aged%2020-29%7D%20%5Ctimes%20100)
⇒Percent of Female over 250 pound aged 20-29= ![\frac{34}{548} \times 100](https://tex.z-dn.net/?f=%5Cfrac%7B34%7D%7B548%7D%20%5Ctimes%20100)
⇒ Percent of Female over 250 pound aged 20-29= ![0.0620437\times 100](https://tex.z-dn.net/?f=0.0620437%5Ctimes%20100)
∴ Percent of Female over 250 pound aged 20-29= ![6.20437 \approx 6.20\%](https://tex.z-dn.net/?f=6.20437%20%5Capprox%206.20%5C%25)
Hence, 6.20% of females aged 20 to 29 weighed over 250 pounds.
Wouldn’t you have to divide or subtract the acute degree with 105 and 30?