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Montano1993 [528]

2 years ago

14

Put the following equation of a line into slope-intercept form, simplifying all fractions. 15x - 3y = 15

1 answer:

MaRussiya [10]2 years ago

8 0

Slope= 5
X-intercept= -5/5 = -1
Y-intercept= 5/1 = 5.0000000

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Tan(-100°) = _____<br><br> -tan80°<br> tan80°<br> tan(-80°)

Anni [7]

Answer:

-tan80°

Step-by-step explanation:

8 0

3 years ago

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Determine the standard form of the equation of the line that passes through (0,5) and (4,0)

Alona [7]

(0,5)(4,0)
slope = (0 - 5) / (4 - 0) = -5/4

y = mx + b
slope(m) = -5/4
use either of ur sets of points....(0,5)...x = 0 and y = 5
now we sub and find b, the y int
5 = -5/4(0) + b
5 = b
so ur equation is : y = -5/4x + 5...but we need it in standard form...

y = -5/4x + 5
5/4x + y = 5....multiply everything by common denominator of 4
5x + 4y = 20 <== standard form of Ax + By = C

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3 years ago

3) Write the operation used to obtain the types of solutions.

Alex Ar [27]

Answer:

the Sum

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3 years ago

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3 years ago

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7. Write the equation of a line which passes through the points (-3,5) and (6,23)

faust18 [17]

Answer:

answer to the equation is

$y = 2x + 11$

Step-by-step explanation:

$y = mx + b$

first find the slope of the line using the two points

$slope \: m = \frac{y2 - y1}{x2 - x1} = \frac{23 - 5}{6 - ( - 3)} \\ = \frac{18}{9} \\ slope \: m = 2$

substitute 2 for m and use one of the points for x and y and solve for b

$5 = 2( - 3) + b \\ 5 = - 6 + b \\ 5 + 6 = b \\ b = 11$

Now that you found b, the y-intercept, you can substitute that into the equation for your line

$y = 2x + 11$

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3 years ago