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Ann [662]
3 years ago
9

Explanation please thank you

Mathematics
1 answer:
GrogVix [38]3 years ago
8 0
300 represents the initial value or the value that you started with.
1.15 is the rate that the function increases by over t (time)

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Examine the following steps. Which do you think you might use to prove the identity Tangent (x) = StartFraction tangent (x) + ta
Over [174]

Answer:

The correct options are;

1) Write tan(x + y) as sin(x + y) over cos(x + y)

2) Use the sum identity for sine to rewrite the numerator

3) Use the sum identity for cosine to rewrite the denominator

4) Divide both the numerator and denominator by cos(x)·cos(y)

5) Simplify fractions by dividing out common factors or using the tangent quotient identity

Step-by-step explanation:

Given that the required identity is Tangent (x + y) = (tangent (x) + tangent (y))/(1 - tangent(x) × tangent (y)), we have;

tan(x + y) = sin(x + y)/(cos(x + y))

sin(x + y)/(cos(x + y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y) - sin(x)·sin(y)) = (Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y))

(Sin(x)·cos(y) + cos(x)·sin(y))/(cos(x)·cos(y))/(cos(x)·cos(y) - sin(x)·sin(y))/(cos(x)·cos(y)) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

∴ tan(x + y) = (tan(x) + tan(y))(1 - tan(x)·tan(y)

6 0
3 years ago
Read 2 more answers
Need help on this PLEASE It is due at 11:40!!! Today!
FrozenT [24]

Answer:

X= 75, Y=30 there you go!

Step-by-step explanation:

5 0
2 years ago
Please help me please​
baherus [9]

Answer:

The answer is C

4 0
3 years ago
How do you find the area of this (it is not 12 or 18) The First answer gets brainliest
bija089 [108]

Answer:

<em><u>ok the area of a trapezoid is 48 </u></em>

a+b divided by two multiplied by height  

Step-by-step explanation:

each square equals 2 so you count by twos instead of ones..

the height is 8   the base is 8 and the top is 4 so

4+8/2=6

6*8=48

6 0
3 years ago
There are 15 students on a yearbook committee. 40% of the students are females. How many students on the committee are males?
Andrei [34K]

Answer:

9 students on the committee are males

Step-by-step explanation:

As per the statement:

There are 15 students on a yearbook committee.

⇒Total students on a yearbook committee = 15

⇒\text{Male students} +\text{Female students} = 15     ....[1]

It is given that:

40% of the students are females

⇒\text{Female students} = \frac{40}{100} \cdot 15 = 6

Substitute in [1] we have;

\text{Male students} + 6 = 15

Subtract 6 from both sides we have;

\text{Male students}= 9

Therefore, 9 students on the committee are males

8 0
3 years ago
Read 2 more answers
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