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Andrew [12]
2 years ago
12

Can i get help on this question x+4= -9 1/4

Mathematics
1 answer:
Bas_tet [7]2 years ago
6 0
Answer:
x=-25/4
Step-by-step explanation:

First your make both sides clean,

x+4=-9/4

Then you minus 4 on both sides to balance the equation:

x+4-4=(-9/4)-4
x= -25/4

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Perform the indicated operation. X^3+43-49x-7x^2 divides by x^2-49
BaLLatris [955]

Answer:

The quotient is: x-7

and remainder is : -300

Step-by-step explanation:

We need to divide X^3+43-49x-7x^2 by x^2-49

First arrange the term  X^3+43-49x-7x^2 in terms of ascending order of x.

Arranging we get:

x^3 - 7x^2 -49x + 43 \  x^2-49

The division steps are shown in figure attached.

The quotient is: x-7

and remainder is : -300

4 0
2 years ago
How did Ramses ll use the military to improve the Egyptian empire?
Travka [436]

True Answer

A. He used military to retake old egyptian territory.

5 0
3 years ago
Is 5 a solution of the equation? 13 - d = 8
crimeas [40]
Yes because 13-5=8. not any other single number can be identified in the missing number
3 0
3 years ago
Read 2 more answers
Find the zeros of the function f(x) = x2 + 5x + 6. A) y = 6 because the graph crosses the y-axis at 6. B) y = -0.25 because that
Fofino [41]

Answer:

D.)

Step-by-step explanation:

The zero's are referencing when y=0, note that when y=0 they are talking about the x-intercepts.  You can graph the function and see when the graph crosses the x-axis or solve for the x-values.  I will solve it via factoring and so:

f(x)=x^2+5x+6

Multiply the outer coefficients, in this case 1 and 6, and 1×6=6.  Now let's think about all the factors of 6 we have: 6×1 and 2×3.  Now is there a way that if we use any of these factors and add/subtract them they will return the middle term 5?  Actually we can say 6-1=5 and 2+3=5.  Let's try both.

First let's use 6 and -1 and so:

x^2+5x+6\\\\x^2+6x-x+6\\\\x(x+6)-1(x-6)

Notice how we have (x+6) and (x-6), these factors do not match so this is incorrect.

Now let's try 2 and 3 and so:

x^2+5x+6\\\\x^2+3x+2x+6\\\\x(x+3)+2(x+3)\\\\(x+2)(x+3)

Notice how the factors (x+3) matched up so this is a factor and so is (x+2), now to solve for the zero's let's make f(x)=0 and solve each factor separately:

Case 1:

f(x)=x+2\\\\0=x+2\\\\x=-2

Case 2:

f(x)=x+3\\\\0=x+3\\\\x=-3

So your zero's are when x=-2 and x=-3.

D.) x=-3 and x=-2 because the graph crosses the x-axis at -3 and -2.


~~~Brainliest Appreciated~~~

8 0
3 years ago
Which square root is between 4 and 5?<br> 10<br> 14<br> 24<br> 32
Alenkinab [10]

Answer:

24

Step-by-step explanation:

4 0
2 years ago
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