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disa [49]
3 years ago
13

What is the y-intercept of the function f()=4-5x? ​

Mathematics
1 answer:
kvasek [131]3 years ago
6 0

Answer:

Step-by-step explanation:

4

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Kamila [148]

Answer:

x-intercept (2,0) or x=2

y-intercept (0,-4)  or y=-4

Step-by-step explanation:

4x-2y>8

2x-y>4

2x-4>y

y<2x-4

y=2x-4

when y=0

2x=4

x=2

x-intercept is (2,0)

and y-intercept is (0,-4)

put x=0,y=0

0-0>8

or 0>8 which is not true. so (0,0) does not lie on the graph.

so graph lies  right of the line .

7 0
3 years ago
If point A is located at (-7,5) and is rotated around 270 clockwise about the origin, then point A' is located at...
jonny [76]

Answer:

B.(-5,-7)

Step-by-step explanation:

According to the rule of rotation if you were to have a 270* clockwise you would first switch the x and y values. Ex: (-7,5) -> (5,-7). next you would make the original y coordinate a negative. (5,-7) -> (-5,-7).

6 0
3 years ago
charmaine purchased a prepaid phone card for $25. Long distance calls cost 6 cents a minute using this card. Charmaine used her
neonofarm [45]

25-23.08=1.92

1.92/0.6=3.2

her call last 3.2minutes

7 0
4 years ago
The port of South Louisiana, located along 54 miles of the Mississippi River between New Orleans and Baton Rouge, is the largest
Ksenya-84 [330]

Answer:

a) 0.7287

b) 0.9663

c) 0.237

d) 3.65 tons of cargo per week or more that will require the port to extend its operating hours.  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  4.5 million tons of cargo per week

Standard Deviation, σ = 0 .82 million tons

We are given that the distribution of number of tons of cargo handled per week is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P( port handles less than 5 million tons of cargo per week)

P(x < 5)

P( x < 5) = P( z < \displaystyle\frac{5 - 4.5}{0.82}) = P(z < 0.609)

Calculation the value from standard normal z table, we have,  

P(x < 5) =0.7287= 72.87\%

b) P( port handles 3 or more million tons of cargo per week)

P(x \geq 3) = P(z \geq \displaystyle\frac{3-4.5}{0.82}) = P(z \geq −1.82926)\\\\P( z \geq −1.82926) = 1 - P(z < -1.829)

Calculating the value from the standard normal table we have,

1 - 0.0337 = 0.9663 = 96.63\%\\P( x \geq 3) = 96.63\%

c)P( port handles between 3 million and 4 million tons of cargo per week)

P(3 \leq x \leq 4) = P(\displaystyle\frac{3 - 4.5}{0.82} \leq z \leq \displaystyle\frac{4-4.5}{0.82}) = P(-1.829 \leq z \leq -0.609)\\\\= P(z \leq -0.609) - P(z < -1.829)\\= 0.271-0.034 = 0.237= 23.7\%

P(3 \leq x \leq 4) = 23.7\%

d) P(X=x) = 0.85

We have to find the value of x such that the probability is 0.85.

P(X > x)  

P( X > x) = P( z > \displaystyle\frac{x - 4.5}{0.82})=0.85  

= 1 -P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.85  

=P( z \leq \displaystyle\frac{x - 4.5}{0.82})=0.15  

Calculation the value from standard normal z table, we have,  

P( z \leq -1.036) = 0.15

\displaystyle\frac{x - 4.5}{0.82} = -1.036\\x = 3.65

Thus, 3.65 tons of cargo per week or more that will require the port to extend its operating hours.

8 0
3 years ago
Solve each of the following equations. (2 answers)<br><br> |2x-3|=2
Roman55 [17]

Answer:

x= 5/2 or 1/2

Step-by-step explanation:

absolute value always gives us positive

if |u| = 2, u can be -2 or 2

2x-3 = 2

2x = 5

x = 5/2

2x-3 = -2

2x = 1

x= 1/2

in general, set the stuff inside the absolute value to equal both positive and negative of the equivalent value

6 0
3 years ago
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