At some point during her free fall, the skydiver reaches her terminal speed. What is the magnitude of the drag force fdrag due t
1 answer:
You might be interested in
The Pythagoras' theorem and the uniform motion allows to find the answer for the rate of change of distance is
v = 32.3 m / s
The distance is the length of the segment that a white house wing with the helicopter, this can be found using the Pythagoras' theorem
R =
Where R is the distance, x is the horizontal distance where the helicopter flies and y is the vertical distance that corresponds to the flight height
y = 500 m
Since the helicopter flies at constant speed, we can use the uniform motion relation
=
x = t
Where is the speed of the helicopter and t is the time
We substitute
r =
Kinematics defines velocity as the change of position in the unit of time
This expression is the change in distance as a function of time for a given speed. In the exercise, this speed is requested for a time of one minute, for the helicopter speed of
v = 2km/min ( ) (
) = 33.33 m / s
Let's calculate
v =
v = 32.3 m / s
In conclusion using the Pythagoras' theorem and the uniform motion we can find the answer for the rate of change in distance is
v = 32.3 m / s
Learn more here: brainly.com/question/343682