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elixir [45]
3 years ago
7

Choose the correct sum of the polynomials (6x3 − 8x − 5) (3x3 6x 2). 9x3 − 2x − 3 3x3 2x 3 3x3 − 2x − 3 9x3 14x 3.

Mathematics
1 answer:
RUDIKE [14]3 years ago
5 0

Like terms have the same variable and power. The sum of the two polynomials (6x^3 -8x -5)+(3x^3+6x+2) is 3x^3 -2x -3.

<h3>What are Like terms?</h3>

Like terms are those terms that are having the same variables, also the variables are of the same order as well.

for example, 25x and 5x are like terms; 30xy and 7xy are like terms, 9x³ and 4x² are not like terms, etc.

We know that in order to find the sum of the two polynomials we need to add or subtract the like terms, therefore, the sum of the polynomials can be done as,

(6x^3 -8x -5)+(3x^3+6x+2)\\\\=  6x^3 -8x -5+3x^3+6x+2\\\\= 6x^3 +3x^3- 8x+6x-5+2\\\\ = 3x^3 -2x -3

Hence, the sum of the two polynomials (6x^3 -8x -5)+(3x^3+6x+2) is 3x^3 -2x -3.

Learn more about Like Terms:

brainly.com/question/2513478

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Lesechka [4]

Answer:

1 quart blue + 1 1/2 quart red

Given:

Ratio of blue paint : red paint = 1/3 : 1/2

simplifying this ratio into whole numbers by multiplying both sides by 2 and 3, we get:

(1/3) x (3x2) : (1/2) x (3x2)

2 : 3

From this we can determine the fractions of red and blue paint used in any total purple mix

fraction of blue paint = 2/(2+3) = 2/5 of purple mix

fraction of red paint = 3/(2+3) = 3/5 of purple mix

we are given that we want to make 2 1/2  (= 5/2) quarts of purple paint

hence

amount of blue paint

= fraction of blue paint in purple mix x total amount of purple paint

= (2/5) x (5/2) = 1 quart

amount of red paint

= fraction of redpaint in purple mix x total amount of purple paint

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Step-by-step explanation:

7 0
3 years ago
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zloy xaker [14]

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Step-by-step explanation:

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Musya8 [376]

t^2\dfrac{\mathrm dy}{\mathrm dt}+y^2=ty

Divide both sides by y^2:

\dfrac{t^2}{y^2}\dfrac{\mathrm dy}{\mathrm dt}+1=\dfrac ty

Let z(t)=\dfrac t{y(t)}, so that y=\dfrac tz and

\dfrac{\mathrm dy}{\mathrm dt}=\dfrac{z-t\frac{\mathrm dz}{\mathrm dt}}{z^2}

so that the ODE is transformed to

z^2\dfrac{z-t\frac{\mathrm dz}{\mathrm dt}}{z^2}+1=z

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and assuming t>0,

\dfrac{\mathrm dz}{\mathrm dt}=\dfrac1t

The remaining ODE is separable:

\mathrm dz=\dfrac{\mathrm dt}t\implies z=\ln t+C

\implies\dfrac ty=\ln t+C

\implies\dfrac yt=\dfrac1{\ln t+C}

\implies y=\dfrac t{\ln t+C}

6 0
4 years ago
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balu736 [363]

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Step-by-step explanation:

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Romashka-Z-Leto [24]
The answer to your question is 40.
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