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vodomira [7]
3 years ago
14

CAN SOMEONE HELP ME​

Mathematics
1 answer:
ANTONII [103]3 years ago
7 0

Answer:

C is the answer

you can also see

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Is 1+4(3x-10)-12x equivalent to-9
Ymorist [56]

Answer:

no

Step-by-step explanation:

Given

1 + 4(3x - 10) - 12x ← distribute the parenthesis

= 1 + 12x - 40 - 12x ← collect like terms

= 1 - 40

= - 39 ≠ - 9

5 0
3 years ago
Salem High School's winter sports teams WON 72% of their games last season. If the teams played 50 games, how many games did the
Dmitriy789 [7]

Answer

Find out the how many games did the teams lose .

To prove

Formula

Percentage = \frac{Part\ value\times 100}{Total\ values}

As given

Salem High School's winter sports teams WON 72% of their games last season.

If the teams played 50 games .

Percentage = 72%

Total value = 50

Put in the formula

72 = \frac{Number\ of\ games\ win\times 100}{50}

Number\ of\ games\ win = \frac{72\times 50}{100}

Number of games win = 36

Number of  games teams loses = Total number of games - number of games win

                                                          = 50 - 36

                                                          = 14

Therefore the number of games  team loses are 14 .



5 0
3 years ago
Find all values of x such that <img src="https://tex.z-dn.net/?f=%5Csqrt%7B4x%5E2%7D%20-%5Csqrt%7Bx%5E2%7D%3D%206" id="TexFormul
tester [92]
There are two answers.
6 and -6
3 0
3 years ago
At the Foremost State Bank the average savings account balance in 2012 was $1900. A random sample of 45 savings account balanes
lakkis [162]

Answer:

The calculated  |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

Step-by-step explanation:

<u><em>Step(i)</em></u>:-

Mean of the Population = 1900

Given random sample size 'n' =  45

Mean of the sample x⁻ = 1000

Standard deviation of the sample = 225

<u><em>Null Hypothesis</em></u>:-

There is no difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012.

<u><em>Alternative Hypothesis</em></u> :-

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

<u><em>Step(ii</em></u>):-

Test statistic

        t = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }

        t = \frac{1000-1900 }{\frac{225}{\sqrt{45} } }

       t = -900 /33.54 = -26.517

      |t| = |-26.517|=26.517

Degrees of freedom

                       γ = n-1 = 45-1 =44

t₍₀.₀₁ , ₄₄₎ = 2.326

The calculated  |t| = |-26.517|=26.517 > 2.326 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is difference between mean savings account balance in 2013 is different from the mean savings account balance in 2012

4 0
3 years ago
Simplify using the order of operations.<br> 3/8-1/9
svetoff [14.1K]

Answer:

19 /72 ≈0.264

Step-by-step explanation:

3 0
3 years ago
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