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olasank [31]
1 year ago
7

In an arithmetic sequence, the first term,

Mathematics
1 answer:
IRINA_888 [86]1 year ago
8 0

Answer:

See below

Step-by-step explanation:

Add 5 to each preceding number

               a_{n} = (a_{n-1})+5

1 9  9

2  14   [9+5]

3  19   [14+5]

4  24  [19+5]

5  29  [24+5]

6 34 34  [29+5]

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Write the set of all real numbers greater than 19 and less than 32 in set-builder notation.
Aleks04 [339]

Answer: {xI x ∈ R, 19 < x < 32}

Step-by-step explanation:

This notation is:

{xI condition1, condition2, ...}

The first condition is:

From what set we take the values of x?

From the set of real numbers.

x ∈ R

The other conditions are the limitations that we have for x, in this case:

19 < x < 32

Then we can write this as:

{xI x ∈ R, 19 < x < 32}

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2 years ago
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Step-by-step explanation:

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AysviL [449]
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