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maks197457 [2]
3 years ago
14

. Keith plans on eating 1 cup of tuna per day for five days. How much tuna does he need? Are 4 cans enough?

Mathematics
2 answers:
vovikov84 [41]3 years ago
7 0
He has too much for 4 cans. He has 5 3/5
cups.
vazorg [7]3 years ago
4 0

Answer:

Keith needs 5 cans of tuna, so no 4 cans are not enough

Step-by-step explanation:

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Helppppppppppppppppppp
Schach [20]

Answer:

1/8^4

Step-by-step explanation:

when divinding exponents with the same base, subtract the power. you get 8^-4. since the problem specifies no negative exponents you need to simplify. this give you 1/8^4

7 0
3 years ago
Use the sequence below to answer parts a and b (8,17,26,35,44,53,...) Create an explicit formula to determine the 12th term of t
Andreyy89
THATS HOW YOU SOLVE THE 12TH AND 7TH TERM

8 0
3 years ago
Find the mean and the mean average height.
-BARSIC- [3]

Answer:

a.) mean=200.3

b.) 210 cm

Step-by-step explanation:

a.) We are given the heights and their frequency. We can make a new set:

198, 199, 199, 199, 200, 200, 201, 201, 201, 201, 201, 202, 202

Now find the mean. The mean is found by adding all the numbers in the set, then dividing the total by the number of terms in the set. Add:

198+199+199+199+200+200+201+201+201+201+201+202+202=2604

Now count the terms. There are 13 terms. Divide the total by the number of terms:

\frac{2604}{13}= 200.3

The mean is 200.3.

b.) Use random values like 200, 198 etc. and add them to the total of the last set, then divide by 14 instead of 13 (because there is a new player). Do this until you get a mean of 201 with the new height:

2604+210=2814\\\\\frac{2814}{14}= 201

For the new mean to be 201 cm, the new player has a height of 210 cm.

Finito.

8 0
3 years ago
A rectangle has an area of 18cm2 (squared). The lengths of the sides are whole numbers. How long could the sides of the rectangl
marishachu [46]

Answer:

9 cm, 2 cm

or

6 cm , 3 cm

Step-by-step explanation:

There are two possibilities of the lengths of the sides of rectangle

18= 9\times 2\\18=6\times 3\\

7 0
3 years ago
The corporate team-building event will cost $8 if it has 4 attendees. How many attendees can
sukhopar [10]
Answer: 22 attendees can attend the corporate team-building event, with a budget of $46.

1. 8 = 4x
2. 8/4 = 4x/4
3. x = 2, each ticket would cost $2 per attendee
4. $46/$2 = 23
8 0
4 years ago
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