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3 years ago

PLEASE HELP ME, I WILL MARK YOU BRAINLIEST!!

Mathematics

1 answer:

Naddika [18.5K]3 years ago

3 0

Answer:

Step-by-step explanation:

Five students= 5x

They all got two more= 5x + 2(5)

5x + 10 = 30

- 10 -10

5x = 20

x = 4

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Car dealers sometimes use the rule of thumb that a car loses about 30% of its value each year. 1. Suppose you bought a new car i

Artemon [7]

Answer: $A=15000(1.30)^t$

Step-by-step explanation:

Formula to find the price of an item after t years after withe a depreciation rate of r% is $A=P(1-\dfrac{r}{100})^t$ , where P = Initial value of item.

Given: P = $15,000, r= 30%

Then, the value of car after t years will be :

$A= 15000(1+\dfrac{30}{100})^t\\\\\Rightarrow\ A=15000(1+0.30)^t\\\\\Rightarrow\ A=15000(1.30)^t$

The required general formula for the value of the car t years after its purchase:

$A=15000(1.30)^t$

7 0

3 years ago

Find the common ratio, r, in the following geometric sequence. 27, 9, 3, 1,…

Shtirlitz [24]

To find the common ratio
divide by the previous numb/number beside it:
$\frac{9}{27}=\frac{1}{3},\:\quad \frac{3}{9}=\frac{1}{3},\:\quad \frac{1}{3}=\frac{1}{3}$

so $r=\frac{1}{3}$

3 0

3 years ago

Read 2 more answers

3. Find x and m_1 3x +8 6x - 22

Sergio039 [100]

Answer:

The answer to your question is: x = 10; 1 = 142°

Step-by-step explanation:

Find x and m∡ 1

We know that 6x - 22 = 3x + 8 Because they are vertical angles

6x - 3x = 22 + 8 Solve for x

3x = 30

x = 10

Then ∡ = 6(10) - 22

= 60 - 22

= 38°

1 = [360 - 2(38) ] / 2

= [360 - 76] / 2

= 284/2

= 142°

3 0

3 years ago

Evaluate the expression when y = 5 and x = 4 x + 7y

Alex

y = 5 and x = 4

x + 7y =

4 + 7(5) =

4 +35 =

3 0

3 years ago

Find (f - g)(x) if f(x) = x2 - x - 6 and g(x) = 2x2 - 3x + 4

Nadya [2.5K]

For this question we just have to re-substitute the expressions for their respective functions by assigning them in a plausible condition for two functions. Here, the first function of "x" is subtracted by a second function of "x". The expressions are assigned according to the first and second function expressions in each case or condition.

All we have to do is distribute the parentheses for second expression to deploy positive addition between 2x^2 and 3x. Furthermore grouping all the like terms to get the required answer to this query. So, let me express this via LaTeX interpreter equation editor for a better understanding and clear all the doubts for these forms of queries.

$\mathbf{Since, \: \: f(x) = x^2 - x - 6}$

$\mathbf{\therefore \quad \Big(x^2 - x - 6 - g(x) \Big) \: (x)}$

$\mathbf{Since, \: \: g(x) = 2x^2 - 3x + 4}$

$\mathbf{\therefore \quad x^2 - x - 6 - (2x^2 - 3x + 4)}$

$\mathbf{x^2 - x - 6 - (2x^2) - (- 3x) - (+ 4)}$

$\mathbf{x^2 - x - 6 - 2x^2 + 3x - 4}$

$\mathbf{x^2 - 2x^2 - x + 3x - 6 - 4}$

$\mathbf{x^2 - 2x^2 + 2x - 6 - 4}$

$\mathbf{- x^2 + 2x - 6 - 4}$

$\boxed{\mathbf{\underline{Required \: \: Answer: \: - x^2 + 2x - 10}}}$

Hope it helps.

6 0

3 years ago