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2 years ago

When can estimating an angle measure be useful in solving a problem?

Mathematics

1 answer:

yarga [219]2 years ago

8 0

Estimating an angle measure in a problem can be useful when the actual angle measurement cannot be determined

<h3>When estimates are useful</h3>

Estimates are simply used to approximate and to guess the actual value of a measured quantity

In angles, when the actual measurement is not known, the estimate can be used in place of the actual value

Hence, estimating an angle measure can be useful when the actual angle measurement cannot be determined

Read more about estimation and approximation at:

brainly.com/question/6768038

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Jasmine borrowed $15,000 for 8 years and she paid $6,600 in interest. What was the interest rate for Jasmine's loan?

weeeeeb [17]

Answer:

5.5%

Step-by-step explanation:

To find the interest rate, use the equation: I = prt

I = Interest = $6,600

p = principal = $15,000

r = rate = unknown

t = time = 8 years

Now plug the numbers into the equation.

6,600 = 15,000 * r * 8

6,600 = 120,000 * r

Now isolate the variable by dividing both sides of the equation by 120,000.

0.055 = r

Now change the rate to a percent by moving the decimal point 2 digits to the right.

5.5% = r OR r = 5.5%

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3 years ago

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Basile [38]

Answer:

Step-by-step explanation:

1. 3x2 + 5x - 4 + 6x2 - x + 7

= combining like terms

= 9x2 + 4x + 3

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= 5y2 - 10y + 1

3. 2x2y - 3xy2 + x2y - 4x2y - 2xy2

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4. x2 - y2 + 2x2 - 3xy + 4y2 + 3y2 - 5xy - x2

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3 years ago

PLEASE HELP The toll to cross a bridge is $1.25. If $72.50

blagie [28]

Answer:

Step-by-step explanation:

all you have to do is divide 1.25 from 72.50

6 0

3 years ago

Refer to the following scenario:You want to see if there is a difference between the exercise habits of Science majors and Math

bekas [8.4K]

Answer:

1. H0: P1 = P2

2. Ha: P1 ≠ P2

3. pooled proportion p = 0.542

4. P-value = 0.0171

5. The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

6. The 99% confidence interval for the difference between proportions is (-0.012, 0.335).

Step-by-step explanation:

We should perform a hypothesis test on the difference of proportions.

As we want to test if there is significant difference, the hypothesis are:

Null hypothesis: there is no significant difference between the proportions (p1-p2 = 0).

Alternative hypothesis: there is significant difference between the proportions (p1-p2 ≠ 0).

The sample 1 (science), of size n1=135 has a proportion of p1=0.607.

$p_1=X_1/n_1=82/135=0.607$

The sample 2 (math), of size n2=92 has a proportion of p2=0.446.

$p_2=X_2/n_2=41/92=0.446$

The difference between proportions is (p1-p2)=0.162.

$p_d=p_1-p_2=0.607-0.446=0.162$

The pooled proportion, needed to calculate the standard error, is:

$p=\dfrac{X_1+X_2}{n_1+n_2}=\dfrac{82+41}{135+92}=\dfrac{123}{227}=0.542$

The estimated standard error of the difference between means is computed using the formula:

$s_{p1-p2}=\sqrt{\dfrac{p(1-p)}{n_1}+\dfrac{p(1-p)}{n_2}}=\sqrt{\dfrac{0.542*0.458}{135}+\dfrac{0.542*0.458}{92}}\\\\\\s_{p1-p2}=\sqrt{0.001839+0.002698}=\sqrt{0.004537}=0.067$

Then, we can calculate the z-statistic as:

$z=\dfrac{p_d-(\pi_1-\pi_2)}{s_{p1-p2}}=\dfrac{0.162-0}{0.067}=\dfrac{0.162}{0.067}=2.4014$

This test is a two-tailed test, so the P-value for this test is calculated as (using a z-table):

$\text{P-value}=2\cdot P(z>2.4014)=0.0171$

As the P-value (0.0171) is bigger than the significance level (0.01), the effect is not significant.

The null hypothesis failed to be rejected.

At a signficance level of 0.01, there is not enough evidence to support the claim that there is significant difference between the exercise habits of Science majors and Math majors .

We want to calculate the bounds of a 99% confidence interval of the difference between proportions.

For a 99% CI, the critical value for z is z=2.576.

The margin of error is:

$MOE=z \cdot s_{p1-p2}=2.576\cdot 0.067=0.1735$