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lidiya [134]
2 years ago
7

When can estimating an angle measure be useful in solving a problem?

Mathematics
1 answer:
yarga [219]2 years ago
8 0

Estimating an angle measure in a problem can be useful when the actual angle measurement cannot be determined

<h3>When estimates are useful</h3>

Estimates are simply used to approximate and to guess the actual value of a measured quantity

In angles, when the actual measurement is not known, the estimate can be used in place of the actual value

Hence, estimating an angle measure can be useful when the actual angle measurement cannot be determined

Read more about estimation and approximation at:

brainly.com/question/6768038

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Solve |p + 2| = 10 {-12} {-8, 8} {-12, 8}
Lena [83]

Hello.

The symbols | | mean the absolute value, which is keeps the numbers postive.

Of the answers shown, the correct answer is {-8, 8) because |-8 + 2| = 10, because of the absolute value symbols | |. (Also |8 + 2| of course equals 10.)

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Identify the area of segment MNO to the nearest hundredth. HELP PLEASE!! I don't understand it!
katrin2010 [14]

Answer:

  13.98 in²

Step-by-step explanation:

I don't understand it, either.

Point N is part of a "segment" that above and to the right of chord MO. It is the sum of the areas of 3/4 of the circle and a right triangle with 7-inch sides. The larger segment MO to the upper right of chord MO has an area of about 139.95 in², which <u>is not</u> an answer choice.

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The remaining segment, to the lower left of chord MO does not seem to have anything to do with point N. However, its area is 13.98 in², which <u>is</u> an answer choice. Therefore, we think the question is about this segment, and we wonder why it is called MNO.

The area of a segment is given by the formula ...

  A = (1/2)(θ -sin(θ))r² . . . . . . where θ is the central angle in radians.

Here, we have θ = π/2, r = 7 in, so we can compute the area of the smaller segment MO as ...

  A = (1/2)(π/2 -sin(π/2))(7 in)² = 24.5(π/2 -1) in² ≈ 13.9845 in²

Rounded to hundredths, this is ...

  ≈ 13.98 in²

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3 years ago
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