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xxTIMURxx [149]
2 years ago
13

Help me pleaseeeeeeeeeeeeeee

Mathematics
1 answer:
boyakko [2]2 years ago
6 0

Answer:

So the top right answer choice (x - 10)² = 80 has the same solution as x² - 20x + 20 = 0

Step-by-step explanation:

Let's solve your equation step-by-step.

x² − 20x + 20 = 0

For this equation: a = 1, b = -20, c = 20

1x² + −20x + 20 = 0

Step 1: Use quadratic formula with a = 1, b = -20, c = 20.

x = −b ± √b² − 4ac / 2a

x = −(−20) ± √(−20)² − 4(1)(20) / 2(1)

x = 20 ± √320 / 2

x = 10 + 4√5 or x = 10 − 4√5

Let's try the top right answer choice

(x−10)² = 80

Step 1: Simplify both sides of the equation.

x² − 20x + 100 = 80

Step 2: Subtract 80 from both sides.

x² − 20x + 100 − 80 = 80 − 80

x² − 20x + 20 = 0

For this equation: a = 1, b = -20, c = 20

1x² + −20x + 20 = 0

Step 3: Use quadratic formula with a = 1, b = -20, c = 20.

x = −b ± √b² − 4ac / 2a

x = −(−20) ± √(−20)² − 4(1)(20) / 2(1)

x = 20 ± √320 / 2

x = 10 + 4√5 or x = 10 − 4√5

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x (x-6) + 3 (x-6) = 0
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7 0
4 years ago
Which algebraic properties was applied to the expression a + (b + c) = (a + b) + c?
andrew11 [14]

Answer:

the Associative Property

Step-by-step explanation:

Notice that the ORDER doesn't change -- a, b, c on both sides.  But the GROUPING changes.

Example:

3 + (4 + 5) = (3 + 4) + 5

3 + 9 = 7 + 5

12 = 12

Subtraction does NOT behave this way!

8 - (7 - 1) = 8 - 6 = 2

(8 - 7) - 1 = 1 - 1 = 0

It matters who you associate with!  :-)

5 0
3 years ago
HELP ASAP PLSS BUT only answer if you know it's correct
kvasek [131]
= it is equal to because the absolute value of |-5| is 5
6 0
2 years ago
Read 2 more answers
Indicate whether the statement is true of false.
yawa3891 [41]

The statement is false, as the system can have no solutions or infinite solutions.

<h3>Is the statement true or false?</h3>

The statement says that a system of linear equations with 3 variables and 3 equations has one solution.

If the variables are x, y, and z, then the system can be written as:

a_1*x + b_1*y + c_1*z = d_1\\\\a_2*x + b_2*y + c_2*z = d_2\\\\a_3*x + b_3*y + c_3*z = d_3

Now, the statement is clearly false. Suppose that we have:

a_1 = a_2 = a_3\\b_1 = b_2 = b_3\\c_1 = c_2 = c_3\\\\d_1 \neq d_2 \neq  d_3

Then we have 3 parallel equations. Parallel equations never do intercept, then this system has no solutions.

Then there are systems of 3 variables with 3 equations where there are no solutions, so the statement is false.

If you want to learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

3 0
2 years ago
How do i do this? jshdjahs jt said 20 characters
Charra [1.4K]
Run around the circle until u think it’s right
6 0
4 years ago
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