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2 years ago

(b) 2sin(theta) + 1/sin(theta) - 1 = 0 for 0 <_ x < 2x

Mathematics

1 answer:

Lady bird [3.3K]2 years ago

8 0

Answer:

2 - 2 cos²x = sin x

2 = sin x + 2 cos² x

0 = -2 + sin x + 2(1 - sin² x)

0 = -2 sin² x + sin x + 2 - 2

0 = 2 sin² x - sin x 0 = sin x (2 sin x - 1)

sin x = 0 v sin x = 0.5

x10° + k.360° x1 = 0°, 360°

x2 = (180° - 0°) + k.360°

x2 = 180°

x3 = 30° + k.360°

x3 = 30°

x4 = (180° -30°) + k.360° x4 = 150°

HP: {x | 0°, 30°, 150°, 180°, 360°)

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Evaluate 8-m/n +m when m=8 and n=2

RUDIKE [14]

Substitute the answer: therefore, 8-8/2+8= 0/10 in fraction form, but as you feather simplify 0 divide by 10 you'll get the answer as 0.

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3 years ago

A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len

Gnom [1K]

Answer:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

E. -0.723

$df=n-1=93-1=92$

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

$\bar X=5.97$ represent the sample mean for the length

$s=0.4$ represent the sample standard deviation

$n=93$ sample size

$\mu_o =6$ represent the value that we want to test

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:

Null hypothesis: $\mu = 6$

Alternative hypothesis: $\mu \neq 6$

since we don't know the population deviation the statistic is:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

Replacing in formula (1) we got:

$t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723$

E. -0.723

P value

The degrees of freedom are given by:

$df=n-1=93-1=92$

Since is a two tailed test the p value would be:

$p_v =2*P(t_{(92)}$

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

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3 years ago

An engineer is going to redesign an ejection seat for an airplane. the seat was designed for pilots weighing between 130lb and 1

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Answer: 0.4758

Step-by-step explanation:

Given : Mean : $\mu=137\text{ lb}$

Standard deviation : $\sigma =28.9\text{ lb}$

Also, the new population of pilots has normally distributed .

The formula to calculate the z-score :-

$z=\dfrac{x-\mu}{\sigma}$

For x=130 lb .

$z=\dfrac{130-137}{28.9}=-0.2422145\approx-0.24$

For x=171lb.

$z=\dfrac{171-137}{28.9}=1.1764705\approx1.18$

The p-value = $P(-0.24$

$=0.8809999-0.4051651=0.4758348\approx0.4758348\approx0.4758$

Hence, the required probability : 0.4758

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3 years ago

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ziro4ka [17]

For $z$ and $x$ to be inversely proportional, there must be some constant $k$ such that

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Then when $x=21$ , we have

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sineoko [7]

1. is b
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3 years ago

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