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8_murik_8 [283]
3 years ago
14

Which relationships have the same constant of proportionality between y and x as in the equation below? Select the 3 correct ans

wers

Mathematics
1 answer:
eimsori [14]3 years ago
8 0

Answer:

C, E, and F are correct.

Step-by-step explanation:

You might be interested in
Select all the statements that are true for the following systems of equations.
Dvinal [7]
Answer:

The true statements are:

the first statement: Systems A and C have the same solution
the fourth statement: System C simplifies to 2x - 3y = 4 and 4x - y = 18
the fifth statement: Systems A and B have different soltuoins.

Explanation:

1) The first statement: systems A and C have the same solutiotn: TRUE

The fourth statement proves that that the two systems are equivalent which means that both have the same solution.

2) The second statement: All three systems have different solutions: FALSE

The fourth statement proves that the systems A and C have same solution, so this second statement is false.

3) The third statement: Systems B and C have the same solution: FALSE

<span>You can solve the two systems and will find the solutions are different

Solution of system B.

3x - 4y = 5
y = 5x + 3

replace y = 5x + 3 in the first equation => 3x - 4(5x + 3) = 5

=> 3x - 20x - 12 = 5

=> - 17x = 5 + 12

=> -17x = 17

=> x = - 17 / 17

=> x = - 1

y = 5x + 3 = 5(-1) + 3 = - 5 + 3 = - 2

=> solution x = -1 and y = -2

Solution of system C.

2x - 3y = 4
12x - 3y = 54

subtract
</span>
4) fourth statement: System C simplifies to <span>2x - 3y = 4 and 4x - y = 18 by dividing the second equation by three: TRUE

Look:

Second equation of system C = 12x - 3y = 54

Divide by 3:

12x - 3y     54
----------- = -----
     3           3

Distributive property:

12x      3y      
------ - ----- = 18
   3        3

4x - y = 18, which is the same second equation of system A, so the system C simplifies to the same system A, which is 2x - 3y = 4 and 4x - y = 18.

5) The fifth statement: systems A and B have different solutions: TRUE

</span><span>You can solve the two systems and will find the solutions are different

Solution of system A:

  2x - 3y =  4     
12x - 3y = 54           since it is equivalent to 4x - y =  18
-------------------
12x - 2x = 54 - 4      subtracting the first equation from the secon

10x = 50                  adding like terms

x = 5                        dividing by 10

From 2x - 3y = 4 => 3y = 2x - 4 = 2(5) - 4 = 10 - 4 = 6

=> y = 6 / 3 = 2

=> x = 5, y = 2

Solution of system B.

3x - 4y = 5
y = 5x + 3

replace y = 5x + 3 in the first equation => 3x - 4(5x + 3) = 5

=> 3x - 20x - 12 = 5

=> - 17x = 5 + 12

=> -17x = 17

=> x = - 17 / 17

=> x = - 1

Which is enough to prove that the two systems have different solutions.</span>
5 0
3 years ago
Suppose a production line operates with a mean filling weight of 16 ounces per container. Since over- or under-filling can be da
miss Akunina [59]

Answer:

From the question we are told that

   The  population mean is  \mu  =  16

    The sample size is  n  =  30  

     The  sample mean is  \= x =  16.32

     The  population standard deviation is  \sigma  =  0.8

      The  level of significance is  \alpha  = 0.10

Step 1: State hypotheses:

The  null hypothesis is  H_o :  \mu = 16

The alternative hypothesis is  H_a :  \mu \ne  16

Step 2: State the test statistic. Since we know the population standard deviation and the sample is large our test statistics is

          t = \frac{ \= x  -\mu }{ \frac{\sigma}{ \sqrt{n} } }

=>       t = \frac{ 16.32  -16  }{ \frac{0.8 }{ \sqrt{30} } }

=>       t =2.191

Generally the degree of freedom is mathematically represented as

          df  =  n - 1

=>      df  =  30  - 1

=>      df  =29

Step 3: State the critical region(s):

From the student t-distribution table the critical value corresponding to  \alpha  = 0.10  is

         t = 1.311

Generally the critical regions is mathematically represented as  

         - 1.311 < T <  1.311

Step 4: Conduct the experiment/study:

Generally the from the value obtained we see that the t value is outside the critical region so  the decision is [Reject the null hypothesis ]  

Step 5: Reach conclusions and state in English:

  There is  sufficient evidence to show that the filling weight has to be adjusted

Step 6: Calculate the p-value associated with this test. How does this the p-value support your conclusions in Step 5?

From the student t-distribution table the probability value to the right corresponding to t =2.191 at  a degree of freedom of  df  =29  is

        P( t > 2.191) =  0.0183

Generally the p-value is mathematically represented as

       p-value  = 2 * P( t >  2.191 )

=>    p-value  = 2 * 0.0183

=>    p-value  =  0.0366

Generally  looking at the value obtained we see that p- value <  \alpha hence

The decision rule is

Reject the null hypothesis

Step-by-step explanation:

4 0
3 years ago
Write a problem that the expression 3(-7) -10 + 25 = -6
Sav [38]
This is true because the answer is -6 = -6
7 0
4 years ago
Read 2 more answers
#3. And please give me the work
BARSIC [14]
The answer is 3 1/8 inches
5 0
3 years ago
Which of the following is not part of a mortgage payment?
irakobra [83]

The Answer is: C. taxes

3 0
4 years ago
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