Using a system of equations, it is found that Susan had 44 quarters, 11 dimes and 27 nickels.
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We are going to use:
- x as the number of quarters.
- y as the number of dimes.
- z as the number of nickels.
A <em>quarter </em>is worth $0.25. A <em>dime </em>is worth $0.1, and a <em>nickel </em>is worth $0.05. Total of $13.45, then:

4 times as many <u>quarters as dimes</u>, thus:

16 less <u>dimes than nickels</u>, thus:

Replacing in the first equation, we find x:





Now, with x, we find y and z:


Susan had 44 quarters, 11 dimes and 27 nickels.
A similar problem is given at brainly.com/question/24342899