To find the product of (4x-5y)^2,
we can rewrite the problem as:
(4x-5y)(4x-5y) (two times because it is squared)
Now, time to use that old method we learned in middle school:
FOIL. (Firsts, Outers, Inners, and Lasts)
FOIL can help us greatly in this scenario.
Let's start by multiplying the 'Firsts' together:
4x * 4x = <em>16x^2</em>
Now, lets to the 'Outers':
4x * -5y = <em>-20xy</em>
Next, we can multiply the 'Inners':
-5y * 4x = <em>-20xy</em>
Finally, let's do the 'Lasts':
-5y * -5y = <em>25y</em>^2
Now, we can take the products of these equations from FOIL and combine like terms. We have: 16x^2, -20xy, -20xy, and 25y^2.
-20xy and -20xy make -40xy.
The final equation (product of (4x-5y)^2) is:
16x^2 - 40xy + 25y^2
Hope I helped! If any of my math is wrong, please report and let me know!
Have a good one.
Answer:
D. 58,000 :)
Step-by-step explanation:
We need to multiply to find the answer!
14,500 x 4 = 58000
Havean amazing day!!
Please rate and mark brainliest!!
Answer:
28 cans is the correct answer
Step-by-step explanation:
Answer:
Step-by-step explanation:
let f(x)=y
y=2x+5
flip x and y
x=2y+5
2y=x-5
y=(x-5)/2
f^{_1}(x)=(x-5)/2
but f^{-1}(x)=1
so (x-5)/2=1
x-5=2
x=2+5=7