Help please. KHAN ACADEMY!!!

Why is (12-23) • 2 not the same as 12-(3•2)

RoseWind [281]

Step-by-step explanation:

Note the system of equation, PEMDAS. First, you solve parenthesis, then multiplication, then subtraction.

In this case, solve each of the expression given to us. Remember that parenthesis is first:

(12 - 23) * 2 = (-11) * 2 = - 22

12 - (3 * 2) = 12 - (6) = 6

- 22 ≠ 6

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3 0

3 years ago

Read 2 more answers

Of the 45 animals on the farm, there are only pigs and chickens. The animals have a total of 124 legs. How many pigs and how man

Bess [88]

Answer:

$on \: this \: farm \: there \: are \to \\ \underline{ \boxed{17 \: pigs }}\: \\ and \\ \underline{ \boxed{28 \:chickens}}$

Step-by-step explanation:

$\\ \underline{ \boxed{solution \: to \: question \: \boxed{ A}}} \\ \\ let \: the \: pigs \: be \to \: p \\ let \: the \: chicks \: be \to \: c \\let \: the \: total \: animals \: be \to \: 45 \\ hence \to \\ p + c = 45.......eq(1) \\ since \: chickens \: have \: two \: legs : \\ while \: pigs \: have \: four \: legs : \\ let \: animals \: with \: 2 \: legs \: be \to \: 2c \\ let \: animals \: with \: 4\: legs \: be \to \: 4p \\ the \: total \: number \: of \: animal \: legs = 124 \\ hence \to \\ 4p + 2c = 124..........eq(2) \\ therefore \: the \: system \: of \: equations \: \\ to \: describe \: the \: situation \: is \to \\ \\ p + c = 45 \\ 4p + 2c = 124 \\ \\ \\ \underline{ \boxed{solution \: to \: question \: \boxed{B }}} \\ \\ \\ we \: could \: apply \: any \: of \: the \: simultanious \\ principles \to \\ here : am \: appling \: the \: elimination \: method \to \\ p + c = 45 \\ 4p + 2c = 124 \\ to \: elimnate \: one \: varaible \: we \: multiply \: by \to \\ (4) \times p + c = 45 \\ (1) \times 4p + 2c = 124 \\ hence \to \\ - \frac{4p + 4c = 180}{4p + 2c = 124} \\next \to \\ 2c = 56 \\ c = \frac{56}{2} \\ \boxed{ c = 28} \\ lets \: work \: for \: p \to \\ p + c = 45 \\ p + 28 = 45 \\ p = 45 - 28 \\ \boxed{p = 17}$

6 0

3 years ago

The data below indicate the time (in seconds) that it takes 25 separate employees to complete a certain task. hw1_q5.csva) What

IgorC [24]

Answer:

Explained below.

Step-by-step explanation:

Consider the data provided.

(a)

Compute the mean of the data in seconds as follows:

Mean =AVERAGE(array)

= 225.280 seconds

(b)

Compute the median of the data in seconds as follows:

Median =QUARTILE.EXC(array,2)

= 229 seconds

(c)

Compute the variance of the data in seconds as follows:

Variance =VAR.S(array)

= 1148.043 seconds

(d)

Compute the standard deviation of the data in seconds as follows:

Standard deviation =STDEV.S(F2:F26)

= 33.883 seconds.

(e)

Compute the median of the data in minutes as follows:

Median =QUARTILE.EXC(array,2)

= 3.755 minutes.

(f)

Compute the median of the data in minutes as follows:

Median =QUARTILE.EXC(array,2)

= 3.817 minutes

(g)

Compute the variance of the data in minutes as follows:

Variance =VAR.S(array)

= 0.319 minutes

(h)

Compute the standard deviation of the data in minutes as follows:

Standard deviation =STDEV.S(F2:F26)

= 0.565 minutes.

3 0

3 years ago

OK I KNOW U CAN DO THIS SO PLS HELP!!!

AleksandrR [38]

Y/4-3. When y=20, it will equal 2. 20/4 is 5, minus 3 is 2.

4 0

3 years ago

Suppose each of the object's three dimensions is increased by a factor of 2 without changing the material of which the object is

KIM [24]

The density change by a factor of 0.125 if the dimensions is increased by a factor of 2

Density is the ratio of mass to the volume. It is given by:

Density (D) = mass (m) / volume (V)

Volume (V) = length (l) * width (w) * height (h)

V = lwh

D = m/lwh

If the dimensions increased by a factor of 2:

V = 2l * 2w * 2h = 8lwh

The new density (D')

D' = m / (8lwh)

D' = 0.125D

The density change by a factor of 0.125 if the dimensions is increased by a factor of 2

Find out more on density at: brainly.com/question/24720428

6 0

3 years ago