102 thts the anwser ur welcome
Answer:

Step-by-step explanation:

Answer:
<em>a) g(-2) = 0</em>
<em>b) g(-1) =1</em>
<em>c) g(4) = 2</em>
Step-by-step explanation:
Given data



<u><em>Step( i )</em></u>:-

put x = -2

<em>g(-2) = 0</em>
<u><em>Step(ii)</em></u>:-

Put x = -1

<em>g(-1) =1</em>
<u><em>Step(iii)</em></u>:-

<em>g(4) = 2</em>
<em></em>
Answer:
The inequality describing the situation is:

Step-by-step explanation:
Joe works as a busboy at the rate of = $7 per hour
Let the number of hours he works as a bus boy this month be =
hours
∴ Amount Joe would make this month working as a busboy =
Joe works as a theater usher at the rate of = $9 per hour
Let the number of hours he works as a theater usher this month be =
hours
∴ Amount Joe would make this month working as a theater usher =
Total amount Joe would make this month =
His goal is earn more than $1500 this month.
∴ The situation can be represented in the following inequality:

Answer:
<h2>For c = 5 → two solutions</h2><h2>For c = -10 → no solutions</h2>
Step-by-step explanation:
We know

for any real value of <em>a</em>.
|a| = b > 0 - <em>two solutions: </em>a = b or a = -b
|a| = 0 - <em>one solution: a = 0</em>
|a| = b < 0 - <em>no solution</em>
<em />
|x + 6| - 4 = c
for c = 5:
|x + 6| - 4 = 5 <em>add 4 to both sides</em>
|x + 6| = 9 > 0 <em>TWO SOLUTIONS</em>
for c = -10
|x + 6| - 4 = -10 <em>add 4 to both sides</em>
|x + 6| = -6 < 0 <em>NO SOLUTIONS</em>
<em></em>
Calculate the solutions for c = 5:
|x + 6| = 9 ⇔ x + 6 = 9 or x + 6 = -9 <em>subtract 6 from both sides</em>
x = 3 or x = -15