Answer:
Here's what I get
Step-by-step explanation:
I plotted the triangles in the diagram below.
Part A
The scale factor for dilation is ½, because every coordinate has been halved.
P (8, 0) ⟶ P' (4, 0)
Q (6, 2) ⟶ Q' (3, 1)
R (-2, -4) ⟶ R' (-1, -2)
Part B
When you reflect a point (x, y) about the y-axis, the y-coordinate remains the same, but the x-coordinate gets the opposite sign. Thus,
P' (4,0) ⟶ P" (-4,0)
Q' (3,-1) ⟶ Q" (-3,-1)
R' (-1,-2) ⟶ R" (1,-2)
∆P"Q"R" has coordinates P" (-4,0), Q" (-3,-1), R"(1,-2).
Part C
∆PQR and ∆ P"Q"R" are not congruent, because corresponding sides are not equal.
Answer:
asdddasdasdas
Step-by-step explanation:
adsssdddddddddasdssadasdasdasdadsadsa
Answer:
6) Last week, Jonatha's Ice Creamery sold 20 sundaes with nuts and 30 sundaes without nuts What is the ratio of the
Step-by-step explanation:
7:5 or 5:7
9514 1404 393
Answer:
4096∠0°
Step-by-step explanation:
The polar form of the base value is 2∠120°. Then the 12-th power is ...
(2^12)∠(12×120°) = 4096∠0° . . . . or θ = 0 radians, as you wish
_____
I prefer the simpler notation r∠θ, rather than ...
r(cos(θ) +i·sin(θ)) or r·cis(θ) or r·e^(iθ)
You might not see this notation very often in areas outside of electrical engineering.
The large triangle is isosceles, so that the two smaller triangles that appear inside the large one have bases of 12/2, or 6.
Let's see how x and y are related:
sin 60 degrees = opp/hyp = x/y = sqrt(3) / 2
and cos 60 degrees = adj/hyp = 1/2 = 6 / y. Then y = 12 (which should be no surprise, since the large triangle is equilateral).
Then: x/y = sqrt(3) / 2, or
x sqrt(3) x
---- = ----------- = ------ , so that 2x = 12sqrt(3), or x=6sqrt(3).
y 2 12
In summary,
x = 6√3
y=12
