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dezoksy [38]
3 years ago
13

A history test has 30 questions. A student answers 90% of the questions correctly. How many questions did the student get correc

t.
Mathematics
1 answer:
algol133 years ago
7 0

Answer:

27 questions

Step-by-step explanation:

Hope this helps!

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zhenek [66]
1. x-2(2x-3.5)=-14
    x-4x+7=-14
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    x=7
2. y=2(7)-3.5
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hope this helps!
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For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim
Marina86 [1]

Area of the shaded region $=36(\pi -2) square cm

Perimeter of the shaded region =6 (\pi + 2\sqrt 2) cm

Solution:

Radius of the quarter of circle = 12 cm

Area of the shaded region = Area of quarter of circle – Area of the triangle

                                             $=\frac{1}{4} \pi r^2 - \frac{1}{2} bh

                                             $=\frac{1}{4} \pi \times 12^2 - \frac{1}{2} \times  12 \times 12

                                             $=36\pi -72

                                             $=36(\pi -2) square cm.

Area of the shaded region $=36(\pi -2) square cm

Using Pythagoras theorem,

AC^2=AB^2+BC^2

AC^2=12^2+12^2

AC^2=288

Taking square root on both sides of the equation, we get

AC= 12\sqrt 2 cm

Perimeter of the quadrant of a circle = \frac{1}{4} \times 2\pi r

                                                             $=\frac{1}{4} \times 2 \times \pi \times 12

                                                             $=6 \pi cm

Perimeter of the shaded region = 6 \pi + 12\sqrt 2 cm

                                                    =6 (\pi + 2\sqrt 2) cm

Hence area of the shaded region $=36(\pi -2) square cm

Perimeter of the shaded region =6 (\pi + 2\sqrt 2) cm

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Answer:

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Step-by-step explanation:

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