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dezoksy [38]
2 years ago
13

A history test has 30 questions. A student answers 90% of the questions correctly. How many questions did the student get correc

t.
Mathematics
1 answer:
algol132 years ago
7 0

Answer:

27 questions

Step-by-step explanation:

Hope this helps!

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How do i solve that question?
yawa3891 [41]

a) The solution of this <em>ordinary</em> differential equation is y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2   } }.

b) The integrating factor for the <em>ordinary</em> differential equation is -\frac{1}{x}.

The <em>particular</em> solution of the <em>ordinary</em> differential equation is y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}.

<h3>How to solve ordinary differential equations</h3>

a) In this case we need to separate each variable (y, t) in each side of the identity:

6\cdot \frac{dy}{dt} = y^{4}\cdot \sin^{4} t (1)

6\int {\frac{dy}{y^{4}} } = \int {\sin^{4}t} \, dt + C

Where C is the integration constant.

By table of integrals we find the solution for each integral:

-\frac{2}{y^{3}} = \frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32} + C

If we know that x = 0 and y = 1<em>, </em>then the integration constant is C = -2.

The solution of this <em>ordinary</em> differential equation is y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2   } }. \blacksquare

b) In this case we need to solve a first order ordinary differential equation of the following form:

\frac{dy}{dx} + p(x) \cdot y = q(x) (2)

Where:

  • p(x) - Integrating factor
  • q(x) - Particular function

Hence, the ordinary differential equation is equivalent to this form:

\frac{dy}{dx} -\frac{1}{x}\cdot y = x^{2}+\frac{1}{x} (3)

The integrating factor for the <em>ordinary</em> differential equation is -\frac{1}{x}. \blacksquare

The solution for (2) is presented below:

y = e^{-\int {p(x)} \, dx }\cdot \int {e^{\int {p(x)} \, dx }}\cdot q(x) \, dx + C (4)

Where C is the integration constant.

If we know that p(x) = -\frac{1}{x} and q(x) = x^{2} + \frac{1}{x}, then the solution of the ordinary differential equation is:

y = x \int {x^{-1}\cdot \left(x^{2}+\frac{1}{x} \right)} \, dx + C

y = x\int {x} \, dx + x\int\, dx + C

y = \frac{x^{3}}{2}+x^{2}+C

If we know that x = 1 and y = -1, then the particular solution is:

y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}

The <em>particular</em> solution of the <em>ordinary</em> differential equation is y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}. \blacksquare

To learn more on ordinary differential equations, we kindly invite to check this verified question: brainly.com/question/25731911

3 0
2 years ago
Nina has $5 bills and $10 bills in her wallet. she has a total of 7 bills with a value of $55. how many of each type of bill doe
oee [108]
The answer is 3 fives and 4 tens
7 0
3 years ago
Please help on this question, I will really appreciate it. I will definitely give brainliest to the answer whom gives the full P
alukav5142 [94]

Answer and step-by-step explanation:

Here is the proof!

  1. UR II ST - Given
  2. m<USR = m<SUT - Alternate interior angles
  3. m<R = m<T = 90º - Given
  4. US = US - Reflexive property
  5. Triangle RSU = Triangle TUS - AAS {2,3,4}

Hope this helps!!

7 0
3 years ago
Read 2 more answers
5 + 7x = 4x + 8 What is it?​
DaniilM [7]

Answer:

X=1

Hope that helps

7 0
3 years ago
A boat rental company offers two different rental packages. The first rental package costs $45, plus $29.50 per hour. The second
vampirchik [111]

Answer:

1.6 hr

Step-by-step explanation:

1st rental package: y = 29.50x + 45

2nd rental package: y = 0.70x + 90

Set the equation equal to each other;

29.50x + 45 = 0.70x + 90

Subtract 0.70x from both sides;

28.8x + 45 = 90

Subtract 45 from both sides;

28.8x = 45

Divide both sides by 28.8

x = 1.5625 ≈ 1.6

8 0
2 years ago
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