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Jobisdone [24]
2 years ago
8

Read the problem.

Mathematics
2 answers:
Firlakuza [10]2 years ago
5 0
Ed spent $20 at the movies
melisa1 [442]2 years ago
3 0
ANSWER: ⇒ $20

Formulate:

50 × 40%

Calculate:

50 × 0.4

Calculate the product or quotient:

20
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If the area A of a triangle is 60sq m (square meters) and the base b is 20m (meters) what is the altitude of h
umka2103 [35]

Answer:

<u>The altitude or height of the triangle is 6 meters.</u>

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Area of a triangle = 60 m²

Base = 20 m

2. What is the altitude (h) of the triangle?

Let's recall that the formula of the area of a triangle is:

Area = (Base * Height)/2

Replacing with the real values, we have:

60 = (20 * Height)/2

60 * 2 = (20 * Height) (Multiplying by 2 at both sides)

120 = 20 Height

Height = 120/20 = 6 meters

<u>The altitude or height of the triangle is 6 meters.</u>

8 0
3 years ago
In right triangle ABC, shown below, cos C 9√130/9 find AC.
Afina-wow [57]

Answer:

<h2>AC = 9</h2>

Step-by-step explanation:

cosine=\dfrac{adjacent}{hypotenuse}\\\\\text{We have:}\\\\\cos C=\dfrac{9\sqrt{130}}{130}\\\\adjacent=AC\\\\hypotenuse=\sqrt{130}\\\\\text{Substitute:}\\\\\dfrac{9\sqrt{130}}{130}=\dfrac{AC}{\sqrt{130}}\qquad\text{cross multiply}\\\\130AC=(9\sqrt{130})(\sqrt{130})\qquad\text{use}\ \sqrt{a}\cdot\sqrt{a}=a\\\\130AC=(9)(130)\qquad\text{divide both sides by 130}\\\\\dfrac{130AC}{130}=\dfrac{(9)(130)}{130}\\\\AC=9

6 0
3 years ago
Help me work this out
Bogdan [553]
X/-2 + 5 = 7
        -5    -5
x/-2 = 2
*-2      *-2
x = -4
4 0
3 years ago
What is this slope of the line passing through (-7, -10) and (-20, -7)
OLEGan [10]

Rise/Run.

The answer comes out as -3/13

7 0
3 years ago
5•23+5+7+8+9+5+12+3•4
Whitepunk [10]

Answer: 173

Step-by-step explanation:

You would want to follow the order of operations.

So first, multiply 5 and 23, and 3 and 4

5•23+5+7+8+9+5+12+3•4

You will now have:

115+5+7+8+9+5+12+12

Then, just add everything together:

= 173

8 0
3 years ago
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