Question

I need help please this is confusing

Answer 1

Step-by-step explanation:

slope formula when it's perpendicular : m1 × m = -1

Now Differentiate the quadratic function given.

d/dx ( x^2 - x + 1 ) at an x value of -1 from the point "(-1 , 3 )"

= 2x - 1 .... plug in the x value

= 2 × -1 - 1 = -3.

Use this equation...

y - y1 = m(x - x1)

m = slope = derivative at x = -1

y1 = value found by subbing -1 into the original function

x1 = the x value often given.

y - 3 = 1/3 (x + 1)

= 1/3x + 1/3 + 3

y = 1/3x + 10/3.

not sure about this one - it probably intersects at the x & y intercepts of the equation of the normal line.

y = 0 + 10/3 = 10/3

1/3x = 0 - 10/3

x = -10/3 / 1/3 = -10

so the point .... (-10 , 10/3)