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Step2247 [10]
3 years ago
7

Math short answer help!!!? Dakota's math test grade was 7 points less than his science test grade . the sum of the grades was 18

3% what did Dakota get on his math test??
Mathematics
2 answers:
cricket20 [7]3 years ago
6 0
<span>Math short answer help!!!? Dakota's math test grade was 7 points less than his science test grade . the sum of the grades was 183% what did Dakota get on his math test??
88%</span>
Luba_88 [7]3 years ago
3 0

Answer:  Dakota scored 88% in math test.

Step-by-step explanation:  Given that Dakota's math test grade was 7 points less than his science test grade and the sum of the grades in both the grades was 183%.

We are to find the grades that Dakota got in his math test.

Let x% and y% be the grades scored by Dakota in math and science respectively.

Then, according to the given information, we have

x=y-7~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)

and

x+y=183\\\\\Rightarrow (y-7)+y=183~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Uisng equation (i)}]\\\\\Rightarrow 2y-7=183\\\\\Rightarrow 2y=183+7\\\\\Rightarrow 2y=189\\\\\Rightarrow y=\dfrac{190}{2}\\\\\Rightarrow y=95.

From equation (i), we get

x=95-7=88.

Thus, Dakota scored 88% in math test.

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A 2-column table has 4 rows. The first column is labeled x with entries negative 4, negative 2, 3, 3. The second column is label
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10.21 feet.

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_____________________________

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In a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of th
11111nata11111 [884]

Answer:

Required probability is 0.784 .

Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

     Probability that the students passed the second exam = P(S) = 0.72

     Probability that the students passed both exams = P(F \bigcap S) = 0.58

Now, if the student passed the first exam, probability that he passed the second exam is given by the conditional probability of P(S/F) ;

As we know that conditional probability, P(A/B) = \frac{P(A\bigcap B)}{P(B) }

Similarly, P(S/F) = \frac{P(S\bigcap F)}{P(F) } = \frac{P(F\bigcap S)}{P(F) }  {As P(F \bigcap S) is same as P(S \bigcap F) }

                          = \frac{0.58}{0.74} = 0.784

Therefore, probability that he passed the second exam is 0.784 .

5 0
3 years ago
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