Which is the simplified form of p Superscript 0? p StartFraction 1 Over p EndFraction 0 1.
1 answer:
The simplified form of p superscript 0 is equal to the zero power of p, which is 1.
<h3>What is simplified form of a term?</h3>Simplified form of a term is the simplest way of expression the term, by applying the required operations of mathematics.
Given information-
The term given in the problem is p superscript 0.
The term superscript is used for the number which is written above the given number which means power of the number.
Thus the term p superscript 0 can be written as,
Let the simplest form of the given term is . Thus,
In the given number the power of unknown number <em>p </em>is 0. It means the number <em>p</em> has to be multiplied by itself with 0 times.
It can be simply said that the number is the product of no number. When we multiplied with any number with no number, the result should be unity.
Therefore it can be said that, when the power of any number is equal to the zero. Then the result of it equal to the one.
As for the given number, the power is equal to the zero. Thus the result of it should be equal to the one. Therefore,
Hence, the simplified form of p superscript 0 is 1.
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Answer:
The Taylor series of f(x) around the point a, can be written as:
Here we have:
f(x) = 4*cos(x)
a = 7*pi
then, let's calculate each part:
f(a) = 4*cos(7*pi) = -4
df/dx = -4*sin(x)
(df/dx)(a) = -4*sin(7*pi) = 0
(d^2f)/(dx^2) = -4*cos(x)
(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4
Here we already can see two things:
the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.
so we only will work with the even powers of the series:
f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....
So we can write it as:
f(x) = ∑fₙ
Such that the n-th term can written as: