Answer:
(Option B) StartFraction negative 4 Over 3 EndFraction x minus 7 = 1
Step-by-step explanation:
The answer would be 50 and 37.
50-37 = 13
50+37 = 87
THIS IS THE COMPLETE QUESTION BELOW
The demand equation for a product is p=90000/400+3x where p is the price (in dollars) and x is the number of units (in thousands). Find the average price p on the interval 40 ≤ x ≤ 50.
Answer
$168.27
Step by step Explanation
Given p=90000/400+3x
With the limits of 40 to 50
Then we need the integral in the form below to find the average price
1/(g-d)∫ⁿₐf(x)dx
Where n= 40 and a= 50, then if we substitute p and the limits then we integrate
1/(50-40)∫⁵⁰₄₀(90000/400+3x)
1/10∫⁵⁰₄₀(90000/400+3x)
If we perform some factorization we have
90000/(10)(3)∫3dx/(400+3x)
3000[ln400+3x]₄₀⁵⁰
Then let substitute the upper and lower limits we have
3000[ln400+3(50)]-ln[400+3(40]
30000[ln550-ln520]
3000[6.3099×6.254]
3000[0.056]
=168.27
the average price p on the interval 40 ≤ x ≤ 50 is
=$168.27
Answer:
1
Step-by-step explanation:
When turning remainders into mixed numbers remember Place the remainder as the numerator, or the top number, in your fraction. Put the divisor on the bottom of the fraction, or the denominator.
Proceed to check your work :)
hope this helps
9x(6+x)
54x+9x
43x
So in the end the answer after doing the work it will be 43x