Question

Explain Step By Step how to solve the following equation by factoring: 3x^2+22x-45

Answer 1

$\huge \sf \dag \: Answer :$

$\rm 3 {x}^{2} + 22x - 45$

The values of a, b, and c are obtained, namely

• a = 3, b = 22, c = -45

with the values of a, b, and c above we determine the value of x, then :

$\longmapsto \sf x_{1,2} = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a}$

$\longmapsto \sf x_{1,2} = \frac{ - 22 \pm \sqrt{ {22}^{2} - 4(3)( - 45)} }{2(3)}$

$\longmapsto \sf x_{1,2} = \frac{ - 22 \pm \sqrt{484 - 4( - 135)} }{6}$

$\longmapsto \sf x_{1,2} = \frac{ - 22 \pm \sqrt[]{484 + 540} }{6}$

$\longmapsto \sf x_{1,2} = \frac{ - 22 \pm \sqrt{1.024} }{6}$

$\longmapsto \sf x_{1,2} = \frac{ - 22 \pm32}{6}$

with that we get the values of x, namely :

$\longmapsto \rm x_{1} = \bf \frac{10}{6} = 1 \frac{2}{3}$

$\longmapsto \sf x_{2} = \bf - 9$

Solution Set = {1⅔, -9}

-I Hope This Helps!