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svp [43]
2 years ago
10

Help pls thx u! :))))))

Mathematics
2 answers:
sp2606 [1]2 years ago
5 0

Step-by-step explanation:

0.8/1 = x/1.5

Cross multiplication is applied here

0.8 × 1.5 = 1 × x

1.2 = x

Therefore, x = 1.2

Hope it helps.

Stay safe and blessed.

Dima020 [189]2 years ago
4 0
The answer to that is x=1.2
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Answer:

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Step-by-step explanation:

The range is the output values

R: { -8,-3,5,7}

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3 years ago
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Kristin decides to spend at most $50 for a birthday dinner at a restaurant, including a 15% tip.,
Dmitry [639]
0.15x + x <(or equal to) 50
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4 years ago
PLEASE HELP! click on the picture link down below for the question
faust18 [17]

Answer:

b being more than one tells u its not negitive

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that tells u its more than 0

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7 0
3 years ago
Can anyone do 4,5 and 6 for me plz
cricket20 [7]

For  question 4, sinA =\frac{a}{c}, cosA= \frac{b}{c}, tan B = \frac{b}{a}, sin J = \frac{j}{l}, cosK = \frac{j}{l}, tanK = \frac{k}{j}.

Question 5. Option a and question 6. Option j

Step-by-step explanation:

Step 1:

The three basic formula needed to solve these questions are:

sin\theta = \frac{oppositeside}{hypotenuse} , cos\theta = \frac{adjacentside}{hypotenuse}, tan\theta= \frac{opposite side}{adjacent side}.

Step 2:

Using the above formula, we solve the following values

sinA = \frac{oppositeside}{hypotenuse}  =\frac{a}{c}.

cosA = \frac{adjacentside}{hypotenuse} = \frac{b}{c}.

tanB= \frac{opposite side}{adjacent side}= \frac{b}{a}.

sinJ = \frac{oppositeside}{hypotenuse} = \frac{j}{l}.

cosK = \frac{adjacentside}{hypotenuse}= \frac{j}{l}.

tanK= \frac{opposite side}{adjacent side}= \frac{k}{j}.

Step 3:

For question 5, The triangle's angle = 23°, opposite side = BC inches and hypotenuse = 4 inches.

sin\theta= \frac{opposite side}{hypotenuse}. sin 23^{\circ}= \frac{BC}{4}, sin23^{\circ} = 0.3907,BC = (0.3907)(4) = 1.5628.

SO BC is 1.5628 inches, rounding this off to the nearest tenth, we get BC = 1.6 inches which is option a.

Step 4:

For question 6, The triangle's angle = 50°, opposite side = QR m the adjacent side = 8.1 m.

tan\theta= \frac{opposite side}{adjacentside}. tan 50^{\circ}=\frac{QR}{8.1}, tan50^{\circ} = 1.1917,QR = (1.1917)(8.1) = 9.65277

SO QR is 9.65277 meters, rounding this off to the nearest tenth, we get QR = 9.7 inches which is option j.

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Alexeev081 [22]

Answer:

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Step-by-step explanation:

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