**Answer:**

A

**Step-by-step explanation: because a b c are verticles of the fraction 1/3. So if we take 1/3 to a number line you are going to see the verticles of 1/3. Hope this helps.**

The square root of 4 is 2.

**Step-by-step explanation:**

Since you didn't actually ask a question, I'm just going to explain how to get rid of the radicals.

When it comes to radical equations like these, you can usually square both sides to get rid of the radical.

The reason this works is because the "square root" of something is the same as that something raised to the power of 1/2. And when you raise a power to a power, you multiply the two together; which reduces the 1/2 and gets rid of the root. (This is actually true for any root. If you wanted to get rid of a cube root you could cube both sides. If you had a 20th root, you could raise both sides to the power of 20.)

From here you'll either have your answer or perhaps need to continue solving. My work is in the attachment, comment with any questions.

Hey there!

(f * g)(6) is equal to x(x-1) × 3x.

So, let's plug in 6 for x.

(f * g)(6) = 6(6-1) × 3(6)

Subtract inside parenthesis.

(f * g)(6) = 6(5) × 3(6)

Multiply.

(f * g)(6) = 30 × 18

Multiply again.

(f * g)(6) = 540

Hope this helps!

limit formula is:

f(x + h)= (x + h)³ - 3(x + h) + 7

= x³ + 3x²h + 3xh² + h³ - 3x - 3h + 7

f(x) = x³ - 3x + 7

f(x + h) - f(x)= (a³ + 3a²h + 3ah² + h³ - 3a - 3h + 7) - (a³ - 3a + 7)

= 3x²h + 3xh² + h³ - 3h

= = 3x² + 3xh + h² - 3

as h approaches 0: 3x² + 3x(0) + (0)² - 3 = 3x² - 3