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2 years ago

What is 3/4 as a decimal

Mathematics

2 answers:

FromTheMoon [43]2 years ago

4 0

Answer:

three fourths in the decimal formation is 0.75

Lisa [10]2 years ago

3 0

Answer:

0.75 i think idrk for sure.

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What is the correlation coefficient between the variables? Round to three decimal places. Enter your answer in the box. r≈ Age/Q

mafiozo [28]

The correct answer is 0.739 You are rounding to 3 decimal places not 4 :D

6 0

4 years ago

Lin bought x grams of sugar. Jada bought 3⁄4 more than that. Select all equations that represent the relationship between the

adell [148]

Answer:

y = 7/4x

Step-by-step explanation:

Lin bought x grams of sugar.

Jada bought 3⁄4 more than Lin bought.

The equation:

y = x + 3/4x ⇒ y = 7/4x

3 0

3 years ago

In an arithmetic sequence, a3=15 and a8=0. What is the value of a5?

grin007 [14]

The value of a5 is 9

6 0

3 years ago

The diagram shows a circular pond, of radius r metres, surrounded by a circular path.The circular path has a constant width of 1

Alenkasestr [34]

The formula for calculating the area of a circle is expressed as;

A = πr²

Area of the pond = πr²
Area of the path = Area of the path + pond - area of pond

Area of path = π(r+1.5)² - πr²

Since the area of the path is equal to the area of the pond, hence;

π(r+1.5)² - πr² = πr²

Add πr² to both sides

π(r+1.5)² - πr² + πr² = πr² + πr²

π(r+1.5)² = 2πr²

(r+1.5)² = 2r²

Expand the parenthesis

r²+3r + 2.25 = 2r²

r²+3r + 2.25 - 2r² = 0

-r² + 3r + 2.25 = 0

r² - 3r - 2.25 = 0

Multiply through by 2

2r² - 6.0r - 4.5 = 0

This proves the required equation

Learn more on area of composite figures here: brainly.com/question/15981553

3 0

3 years ago

Select the basic integration formula you can use to find the indefinite integral.

kondaur [170]

Answer:

$\int \dfrac{du}{u}=\log|u|+C$

$\int u^n du=\dfrac{u^{n+1}}{n+1}+C$

$\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C$

Step-by-step explanation:

$\int \dfrac{du}{u}=\log|u|+C$ $[\because \int \dfrac{dx}{x}=\log |x|+C]$

$\int u^n du=\dfrac{u^{n+1}}{n+1}+C$ $[\because \int x^n dx=\dfrac{x^{n+1}}{n+1}+C]$

$\int \dfrac{du}{u\sqrt{u^2-a^2}}=\dfrac{1}{a}\csc^{-1}(\dfrac{x}{a})+C$ $[\because \dfrac{adx}{x\sqrt{x^2-a^2}}=\csc^{-1}(\dfrac{x}{a})+C]$

3 0

4 years ago