Answer: see below
Step-by-step explanation:
If this is a 6 sided die then the only possible roll that isnt an odd, a 2, or a 4 is 6.
The probability of something happening is also the probability of something not happening. So in order to not roll an odd, a 2 or a 4 in two rolls, you have to roll a 6 twice.
P = 1 - (1/6)(1/6) = 1 - (1/36) = (35/36)
Answer:
2
3
−
3
2
−
8
−
3
Step-by-step explanation:
General Idea:
The Rules for Transformations of Functions are given below:
If f(x) is the original function, a > 0 and c > 0; Then


Applying the concept:
In the function y=5x^2-2, the effect that the number 5 have on the graph, as compared to the graph of y=x^2 is given below:
C.it stretches the graph vertically by a factor of 5
1 5/8 = 13/8
(13/8)/14 = .116 or 13/112
.116 (26) = 3.016 or 169/56
Answer:
you have to have a value for B and D
Step-by-step explanation: