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Bad White [126]
3 years ago
15

3x3-27x=0 Solve by factoring a

Mathematics
1 answer:
Eddi Din [679]3 years ago
5 0

After factoring 3x^3-27x=0 the solutions are x=0 , x=3, x= -3

Step-by-step explanation:

We need to solve by factoring:

3x^3-27x=0

Solving:

3x^3-27x=0

Taking 3x common:

3x(x^2-9)=0

Now using formula a^2-b^2=(a-b)(a+b)

3x((x)^2-(3)^2)=0\\3x(x-3)(x+3)=0

3x=0\,\,and\,\,x+3=0\,\,and\,\,x-3=0\\x=0\,\,and\,\,x=-3\,\,and\,\,x=3\\

So, After factoring 3x^3-27x=0 the solutions are x=0 , x=3, x= -3

Keywords: Factorization

Learn more about Factorization at:

  • brainly.com/question/1464739
  • brainly.com/question/2568692
  • brainly.com/question/10771256
  • brainly.com/question/1414350

#learnwithBrainly

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Carlos drew a plan for his garden on a coordinate plane. Rose bushes are located at A(–5, 4), B(3, 4), and C(3, –5)
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Given:

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B(3,4)

C(3,-5)

So point D is:

so point D is (-5,-5)

For AB is

Distance between two point is:

\begin{gathered} (x_1,y_1)and(x_2,y_2) \\ D=\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2} \end{gathered}

so distance between A(-5,4) and B(3,4) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(4-4)^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

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For fourth bush point is (-5,-5) it left of point C(3,-5) is:

\begin{gathered} D=\sqrt[]{(3-(-5))^2+(-5-(-5))^2} \\ =\sqrt[]{(8)^2+0^2} \\ =8 \end{gathered}

so fourth bush is 8 unit left of C.

For fourth bush(-5,-5) below to point A(-5,4)

\begin{gathered} D=\sqrt[]{(-5-(-5))^2+(4-(-5))^2} \\ =\sqrt[]{0^2+9^2} \\ =9 \end{gathered}

so fourth bush 9 units below of A.

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