If i understood it right when you estimate the quotient it help you have an idea
Answer:
10 losses
Step-by-step explanation:
Here, we want to get the greatest possible number of games the team lost
Let the number of games won be x
Number drawn be y
Number lost be z
Mathematically;
x + y + z = 38
Let’s now work with the points
3(x) + 1(y) + z(0) = 80
3x + y = 80
So we have two equations here;
x + y + z = 80
3x + y = 80
The greatest possible number of games lost will minimize both the number of games won and the number of games drawn
We can have the following possible combinations of draws and wins;
26-2
25-5
24-8
23-11
22-14
21-17
21-17 is the highest possible to give a loss of zero
Subtracting each sum from 38, we have the following loses:
10, 8, 6, 4, 2 and 0
This shows the greatest possible number of games lost is 10
Answer:
Given the size of rectangular plate in advertisement = 5 cm by 3cm.
Given the condition for length should be = 0.25 of 5 cm
Step-by-step explanation:
Now, have to write the inequality from the given data.
Therefore, 5- 0.25 ≤ L ≤ 5+.25
4.75 ≤ L ≤ 5.25
We know that the area of a rectangle = Length × Width.
Width = 3
Thus, the area is 3 × L
3× (4.75) ≤ 3×L ≤3× (5.25)
14.25 ≤ 3×L ≤ 15.75
So the minimum area is 14.25 cm^2
The maximum area is 15.75 cm^2
Answer:
You need the combinations formula:
Combinations = n! / (r! * (n-r)!)
where n = total # of choices (8) and r = # of choices (4)
Combinations = 8 * 7 * 6 * 5 * 4! / (4! * 4 * 3 * 2 * 1)
Combinations = 8 * 7 * 6 * 5 / 4 * 3 * 2 * 1
Combinations = 7 * 2 * 5
Combinations = 70
Step-by-step explanation: