The complete question is this: This figure (Figure 1) shows a container that is sealed at the top by a movable piston. Inside the container is an ideal gas at 1.00 atm, 20.0 ∘C, and 1.00 L. This information will apply to the first three parts of this problem.
A) What will the pressure inside the container become if the piston is moved to the 1.20 L mark while the temperature of the gas is kept constant?
Explanation:
It is given that,
= 1 atm, = 1 L
= ? , = 1.20 L
As the temperature is constant. Hence, find the value of as follows.
=
=
= 0.833 atm
Thus, we can conclude that the pressure inside the container is 0.833 atm.
consider the right direction as positive and left direction as negative.
M = mass of the ball = 5 kg
m = mass of stone = 1.50 kg
= initial velocity of the ball before collision = 0 m/s
= initial velocity of the stone before collision = 12 m/s
= final velocity of the ball after collision = ?
= final velocity of the stone after collision = - 8.50 m/s
using conservation of momentum
M + m = M + m
(5) (0) + (1.5) (12) = 5 + (1.50) (- 8.50)
= 6.15 m/s
h = height gained by the ball
using conservation of energy
Potential energy gained by ball at Top = kinetic energy at the bottom
Mgh = (0.5) M
(9.8) h = (0.5) (6.15)²
h = 1.93 m
Answer:
The time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.
Explanation:
Given;
average acceleration of the commercial Jet liner, a = 3g = 3 x 9.8 m/s² = 29.4 m/s²
distance traveled by the commercial Jet liner, s = 1542 m
The time taken for the commercial Jet liner to reach the end of its runway is calculated as follows;
s = ut + ¹/₂at²
where;
u is the initial velocity of the commercial Jet liner = 0
s = 0 + ¹/₂at²
s = ¹/₂at²
2s = at²
Therefore, the time taken for the commercial Jet liner to reach the end of its runway is 10.18 s.
Answer:
Explanation: From 13:30 to 15:00, it past: 1 h 30 mins = 1.5
Then, the distance covered by Peter: 40x1.5= 60 miles
From 13:45 to 15:00, it pasts; 1 h 15min =1.25
Then, the distance covered by Philip. 30 x 1.25 = 37.5 miles
Lastly, the distance between them: 60-37.5= 22.5 miles
So the answer is 22.5