Explanation:
a) From Coulombs law,
F = (kq1q2)/r²...............1
F = 10 N
r = 10m
k = 9 × 10^9 m/F
q1 = q2
from equation 1, make q the subject
q = (Fr²)/2k
q = (10×10²)/(2×9×10^9)
q = 1000/1.8×10^10
q = 5.556×10^-8 C
b) K = k/ko
k = Kko = 10times permittivity of free-space
Goodluck
The Coulomb force is equal to the constant k times the product of charge one and charge two over radius.
F=k((q1q2)/r)
Answer:
Gravitation
Explanation:
Gravity, also called gravitation, in mechanics, the universal force of attraction acting between all matter. ... On Earth all bodies have a weight, or downward force of gravity, proportional to their mass, which Earth's mass exerts on them. Gravity is measured by the acceleration that it gives to freely falling objects.
Answer:
The magnetic field strength is 3.9 x 10⁻³ T
Explanation:
The equation for the magnetic field strength produced by a long straight current-carrying wire is written as;
Where;
μ₀ is constant = 4π x 10⁻⁷ N/A
I is the maximum current = 20 A
r is the radius of the wire = 2.053/2 = 1.0265 mm = 1.0265 x 10⁻³ m
Substitute in this values into the equation above;
Therefore, the magnetic field strength is 3.9 x 10⁻³ T
