Answer:
13 quarters, 26 nickels.
Step-by-step explanation:
n will be number of nickels, q will be number of quarters, and we have 39 total coins
so n + q = 39 (number of nickels + number of quarters = 39 coins.
The problem also says there are twice as many nickels as quarters. so we can call the number of nickels n or we can call it 2q (2 times the number of quarters)
which means
n + q = 39
2q + q = 39
3q = 39
q = 13
and she has 2 times as many nickels as quarters... 2 x 13 = 26 nickels
LMK if you have questions.
If you want to double check the money,
n(0.05) + q(0.25) = 4.55 is the equation to use.
26(0.05) + 13(0.25) = 1.3 + 3.25 = $4.55
Answer: A. _3x2x2____
7x2x2
Step-by-step explanation:
given fraction 12/28
here is the numerator = 12 = 2x2x3
here is the Denominator = 28 = 2x2x7
the prime factorization simplest form is _12_= _2x2x3______
28 7x2x2
the simplest form is 12/28 is 3/7
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Hi sorry I’m sorry I did get my message sorry to bother you’re going to be home today I’m sorry I wanna is that the way I do wanna was a good day and I’ml3553248374
The commitment adherence percentage for the week will be 53%.
<h3>How to compute the percentage?</h3>
It was stated that Amy was scheduled to service 17 intervals this week. She picked up 4 more intervals during the week.
The following can be deduced based on the information that are given:
Total intervals = 17
Taken intervals = 4+ 3 + 2 = 9
Therefore, the commitment adherence percentage for the week will be:
= 9/17 × 100
= 53%
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Judy travel's 15.125 miles or 15
miles in 2 3/4 hours
How to solve such time related questions?
The key concept for solving such questions is the relationship between speed, distance and time.
The relationship between them is Distance = Speed x Time
Given:
- Speed = 5 1/2 miles per hour
- Time = 2 3/4 hours
Substituting it in the relationship we get,
Distance = Speed x Time
Distance = 5 1/2 miles per hour x 2 3/4 hours
Distance =
miles
Distance =
miles or 15
miles
Thus Judy travel's 15.125 miles or 15
miles in 2 3/4 hours
Learn more about time related questions here :
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